Let x = # of tickets sold in advance
Let y = # of tickets sold the day of
Cost of the tickets & total sales: 6x & 10y = 6828
You also know y = x + 206
Take the equation mentioned above y = x + 206 and sub it in anywhere the variable y is in the other equations so you'll have this:
6x + 10(x+206) = 6828
Now solve for x to get x = 298
To finish the problem, you must now find the number of y tickets sold.
Sub your x value that you found back into the equation y = x + 206 and you'll get y = 504.
So, 298 tickets were sold in advance and 504 tickets were sold the day of
C. Of the seventh graders, 30% are in the band. If the band has the same number of sixth graders as seventh graders, what percentage of the sixth graders are in the band? Explain how you found your answer.
The inverse of this function is g(x)=9x+2. if this doesn’t work, try g(x)=9x-2 :)
Answer:
A) t > 3
Step-by-step explanation:
960/320 = 3 hours. The question asks "burn <em>more </em>than", meaning the number of hours needs to be more than 3.