P/9 = 90
Multiply 9 to 90 to isolate the variable.
P = 9 x 90
P = 810
The answer is that I think it is 5
Answer:
Part a) ![P=(12h+2)\ yd](https://tex.z-dn.net/?f=P%3D%2812h%2B2%29%5C%20yd)
Part b) The expression that represent the cost of fencing the field is ![(336h+56)](https://tex.z-dn.net/?f=%28336h%2B56%29)
Part c) ![\$1,736](https://tex.z-dn.net/?f=%5C%241%2C736)
Step-by-step explanation:
<u>The complete question in the attached figure</u>
Part a) we know that
The perimeter of the rectangular field (excluding the width of the gate) is equal to
![P=2(L+W)-4](https://tex.z-dn.net/?f=P%3D2%28L%2BW%29-4)
we have
![L=(3h+3)\ yd\\W=3h\ yd](https://tex.z-dn.net/?f=L%3D%283h%2B3%29%5C%20yd%5C%5CW%3D3h%5C%20yd)
substitute the given values
![P=2(3h+3+3h)-4](https://tex.z-dn.net/?f=P%3D2%283h%2B3%2B3h%29-4)
![P=2(6h+3)-4\\P=12h+6-4\\P=(12h+2)\ yd](https://tex.z-dn.net/?f=P%3D2%286h%2B3%29-4%5C%5CP%3D12h%2B6-4%5C%5CP%3D%2812h%2B2%29%5C%20yd)
Part b) we know that
To find out the cost of fencing the field (excluding the gate) , multiply the perimeter by the cost of $28 per yard
so
![28(12h+2)=336h+56](https://tex.z-dn.net/?f=28%2812h%2B2%29%3D336h%2B56)
Part c) we have
h=5
substitute the value of h in the expression of the cost
![336(5)+56=\$1,736](https://tex.z-dn.net/?f=336%285%29%2B56%3D%5C%241%2C736)
Answer:
The TI-84 Plus Silver Edition is powered by four AAA alkaline batteries (not included) , with an automatic shutoff to save energy.
Step-by-step explanation:
Let
x--------> the length side of the original square paper
we know that
<u>the area of the original square paper is equal to</u>
![A1=x*x=x^{2} \ units^{2}](https://tex.z-dn.net/?f=%20A1%3Dx%2Ax%3Dx%5E%7B2%7D%20%5C%20units%5E%7B2%7D%20%20)
<u>the area of the remaining piece of paper is equal to</u>
![A2=x^{2} -2x\\ A2=120\ units^{2} \\ so\\ x^{2} -2x=120\\ x^{2} -2x-120=0](https://tex.z-dn.net/?f=%20A2%3Dx%5E%7B2%7D%20-2x%5C%5C%20A2%3D120%5C%20units%5E%7B2%7D%20%5C%5C%20so%5C%5C%20x%5E%7B2%7D%20-2x%3D120%5C%5C%20x%5E%7B2%7D%20-2x-120%3D0%20)
therefore
<u>the answer is the option </u>
x2 − 2x − 120 = 0