Ok so first you need to put w and x in the equation —-> 13-0.5(10)+6(1/2) and now you just solve -0.5 times 10 is -5 so 13-(-5)+6(1/2) now multiply 6 times 1/2 which is 3 so now we have 13-(-5)+3= 21
Answer:
(-1, 0), (2, 0), (3, 0)
Step-by-step explanation:
x-intercept of a line is defined by a point where y = 0.
So the point in the form of (x, 0) will be the x-intercept of the given continuous function.
From the table attached,
For x = -1, f(-1) = 0
For x = 2, f(2) = 0
For x = 3, f(3) = 0
Points (-1, 0), (2, 0) and (3, 0) are the x-intercepts of the continuous function f(x).
The points if the slope is 4 and the point is (1,-1) are (1,-1) and (2, 3)
<h3>What are linear equations?</h3>
Linear equations are equations that have constant average rates of change, slope or gradient
<h3>How to determine the points?</h3>
The given parameters are:
Slope = 4
Point = (1, -1)
The slope of 4 means that as x changes by 1, the value of y changes by 4
This means that, we have:
(x + 1, y + 4)
Substitute the known values in the above equation
(1 + 1, -1 + 4)
Evaluate
(2, 3)
Hence, the points if the slope is 4 and the point is (1,-1) are (1,-1) and (2, 3)
Read more about linear equations at:
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Answer:
125 degree
Step-by-step explanation:
As m // n, so angle 2 and angle 6 is the same so angle 2 = 55 degree, then angle 1 + angle 2 = 180 degree, so angle 1 = 180 - 55 = 125 degree.
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Answer:

The degrees of freedom are given by:
Now we can calculate the p value with the following probability:

And for this case since the p value is lower compared to the significance level
we can reject the null hypothesis and we can conclude that the true mean for this case is different from 30.6 at the significance level of 0.05
Step-by-step explanation:
For this case we have the following info given:
represent the sample mean
represent the sample deviation
represent the reference value to test.
represent the sample size selected
The statistic for this case is given by:

And replacing we got:

The degrees of freedom are given by:
Now we can calculate the p value with the following probability:

And for this case since the p value is lower compared to the significance level
we can reject the null hypothesis and we can conclude that the true mean for this case is different from 30.6 at the significance level of 0.05