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Sedaia [141]
3 years ago
13

What is the equation in point-slope form for the line parallel to y=3x-3 that contains P(-4,7)?

Mathematics
1 answer:
Darina [25.2K]3 years ago
5 0

Answer:

The answer t oyur question is:     (y -7) = 3(x + 4)

Step-by-step explanation:

Data

Equation point-slope

Line parallel = y = 3x - 3

P (-4, 7)

As the lines are parallels, they have the same slope

slope = 3

Equation slope - point

                                            (y - y1) = m(x - x1)

Substitution                          (y -7) = 3(x + 4)

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(-2, 7) and (-2, 14)<br> Slope
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Which statement is the correct interpretation of the inequality –5 &gt; –6? (1 point)
lilavasa [31]

Answer: OPTION D.

Step-by-step explanation:

The symbol of the inequality ">" means "greater than". Then, -5 is greater than -6.

If a negative number -a is greater than other negative number -b , then the distance between -a and zero is shorter than the distance between -b and zero.

You can see in the number line attached that -5 is closer to 0 than -6. Therefore, -5 is located to the right of -6.

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3 years ago
Two towns have accumulated different amounts of snow. Town 1 has 5 inches of snow so far. Town 2 has 6 inches of snow so far. Ev
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Answer:

<h2>9 hours</h2>

Step-by-step explanation:

This is a fun one, because we just add the respective amounts until we get them to match.

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5

8.5

12

15.5

19

22.5

25

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Town 2:

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3 0
3 years ago
Suppose you first randomly sample one card from a deck of 52. Then, without putting the card back in the deck you sample a secon
Alex787 [66]

Answer:

P(A) = 1201/5525 or 0.2174

The probability that at least one ace will be in the three sampled cards is 1201/5525 or 0.2174

Step-by-step explanation:

Let P(A) represent the probability that at least one ace will be in the three sampled cards.

P(A) = 1 - P(A') ......1

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Number of ace in a standard 52 cards = 4

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P(A) = 1 - 4324/5525

P(A) = 1201/5525 or 0.2174

The probability that at least one ace will be in the three sampled cards is 1201/5525 or 0.2174

7 0
3 years ago
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