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Bas_tet [7]
4 years ago
10

From a survey, a reporter determined that the true estimate for the proportion of citizens who plan to sign a petition is betwee

n 68% and 74%. What is the survey’s margin of error?
Mathematics
2 answers:
Svetradugi [14.3K]4 years ago
7 0
<span>±3% this was the answer from my test </span>
BaLLatris [955]4 years ago
3 0

Answer:

Therefore, the survey's margin of error is ±3%

Step-by-step explanation:

From a survey, a reporter determined that true estimate for the proportion of citizens who plan to sign a petition is between 68% and 74%.

given estimate range = 68% to 74%

Margin of error = (74% - 68%) ÷ 2

6 ÷ 2 = 3%

Therefore, the survey's margin of error is ±3%

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3 0
3 years ago
Read 2 more answers
What would the value of “c” need to be to make this a perfect square trinomial?
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3 0
3 years ago
Of the songs in ivan's music library, 4/5 are rock songs. of the rock songs, 3/4 feature a guitar solo. what fraction of the son
BigorU [14]

In this case this "of" means we will multiply the two fractions "4/5 × 3/4" exists 3/5.

<h3>What are fractions?</h3>

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2 years ago
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Unsure of what you are asking!

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