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Bas_tet [7]
4 years ago
10

From a survey, a reporter determined that the true estimate for the proportion of citizens who plan to sign a petition is betwee

n 68% and 74%. What is the survey’s margin of error?
Mathematics
2 answers:
Svetradugi [14.3K]4 years ago
7 0
<span>±3% this was the answer from my test </span>
BaLLatris [955]4 years ago
3 0

Answer:

Therefore, the survey's margin of error is ±3%

Step-by-step explanation:

From a survey, a reporter determined that true estimate for the proportion of citizens who plan to sign a petition is between 68% and 74%.

given estimate range = 68% to 74%

Margin of error = (74% - 68%) ÷ 2

6 ÷ 2 = 3%

Therefore, the survey's margin of error is ±3%

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