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Elenna [48]
4 years ago
8

If you were to roll the dice one time what is the probability it will land on 4

Mathematics
2 answers:
Thepotemich [5.8K]4 years ago
8 0

Answer:

1/6

there are 6 sides of a dice so the probability it will lad on 4 is 1/4

Step-by-step explanation:

vovangra [49]4 years ago
3 0

Answer: 1/6

Step-by-step explanation: To find the probability of rolling a 4, let's use our ratio for the probability of an event which is shown below.

Number of favorable outcomes/total number of outcomes

Since only one side of a number cube has a 4 on it, the number of favorable outcomes for rolling a 4 is 1 and since there are six sides to a number cube and it's equally likely that the cube will land on any of these sides, the total number of outcomes is 6.

So the probability of rolling a 4 is 1/6 which is equivalent

to 0.167 or 16.7%.

That means it is't likely that you would roll a 4 for instance but it's just as likely as rolling any other number.

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Given :

{\qquad \sf \dashrightarrow  y= 4x + 1 \: –––– \sf \:  (i)}

{\qquad \sf \dashrightarrow   3x + 2y = 13 \: –––– \sf \:  (ii)}

Now, Substituing the value of y in equation (ii) :

{\qquad \sf \dashrightarrow   \: 3x + 2y = 13   }

{\qquad \sf \dashrightarrow   \: 3x + 2(4x + 1) = 13   }

{\qquad \sf \dashrightarrow   \: 3x + 8x + 2 = 13   }

{\qquad \sf \dashrightarrow   \: 11x + 2 = 13   }

{\qquad \sf \dashrightarrow   \: 11x  = 13 - 2   }

{\qquad \sf \dashrightarrow   \: 11x  = 11   }

{\qquad \sf \dashrightarrow   \: x  =  \dfrac{11}{11}    }

{\qquad \sf \dashrightarrow   \bf \: x  = 1   }

Now, substituting the value of x in equation (i) :

{\qquad \sf \dashrightarrow  y= 4x + 1}

{\qquad \sf \dashrightarrow  y= 4(1) + 1}

{\qquad \sf \dashrightarrow  y= 4 + 1}

{\qquad \bf \dashrightarrow  y= 5}

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2 years ago
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