We need to subtract 23 by 12
23-12=11
That means there are 11 girls
Your answer is 11:23
Hope this helped
It’s a little blurry but i can help
Answer:

Step-by-step explanation:
We want to differentiate the equation:

With respect to <em>t</em>, where <em>x, y, </em>and <em>z</em> are functions of <em>t. </em>
<em />
So:
![\displaystyle \frac{d}{dt}\left[x^2-y^3+z^4\right]=\frac{d}{dt}\left[1\right]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7Bd%7D%7Bdt%7D%5Cleft%5Bx%5E2-y%5E3%2Bz%5E4%5Cright%5D%3D%5Cfrac%7Bd%7D%7Bdt%7D%5Cleft%5B1%5Cright%5D)
Implicitly differentiate on the left. On the right, the derivative of a constant is simply zero. Hence:

Answer:
Part 1) AJ drawn the parabola opening upwards, instead of drawing it opening downwards
Part 2) see the explanation
Step-by-step explanation:
Part 1) What mistake did AJ make in the graph?
we have

This is the equation of a vertical parabola written in vertex form
The parabola open downward (because the leading coefficient is negative)
The vertex represent a maximum
The vertex is the point (-2,-1)
therefore
AJ drawn the parabola opening upwards, instead of drawing it opening downwards
Part 2) Evaluate any two x-values (between -5 and 5) into AJ's function. Show your work. How does your work prove that AJ made a mistake in the graph?
take the values x=-4 and x=4
For x=-4
substitute the value of x in the quadratic equation

For x=4
substitute the value of x in the quadratic equation

According to AJ's graph for the value of x=-4 the function should be positive, however it is negative and for the value of x=4 the function should be positive and the function is negative
therefore
AJ made a mistake in the graph