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blsea [12.9K]
3 years ago
12

Marissa claims that stacking 6 blocks with dimensions of One-half times 1 times 1 will give the same volume as stacking 9 blocks

with dimensions of One-third times 1 times 1. Which statements about her claim are true? Check all that apply.
Six of the one-half cubes would have a volume of 3 cubic units.
Nine of the one-third cubes would have a volume of 6 cubic units.
Since One-half and One-third do not have common factors, stacks of one-half cubes and stacks of third-cubes could never have the same volume.
Three of the one-third cubes will make 1 unit cube.
Two of the one-half cubes will make 1 unit cube.
Both stacks will have a volume of 3 cubic units. HURRRY OR ILL GET A F :(
Mathematics
1 answer:
quester [9]3 years ago
8 0

Answer:

  • (A)Six of the one-half cubes would have a volume of 3 cubic units.
  • (D)Three of the one-third cubes will make 1 unit cube.
  • (E)Two of the one-half cubes will make 1 unit cube.
  • (F)Both stacks will have a volume of 3 cubic units.

Step-by-step explanation:

Marissa claims that stacking 6 blocks with dimensions of \frac{1}{2}X1X1  will give the same volume as stacking 9 blocks with dimensions of \frac{1}{3}X1X1  .

First, let us examine the volume of each of the blocks.

<u>For Block 1</u>

The dimensions are:   \frac{1}{2}X1X1

Volume of 1 block =  \frac{1}{2}X1X1= \frac{1}{2} $ cubic units

Volume of 6 blocks of dimension   =6* \frac{1}{2} =3$ cubic units

<u>For Block 2 </u>

The dimensions are:   \frac{1}{3}X1X1

Volume of 1 block =  \frac{1}{3}X1X1=\frac{1}{3} $ cubic units

Volume of 9 blocks of dimension =9*\frac{1}{3} =3$ cubic units  

The following statements out of Marissa's claim are true:

(A)Six of the one-half cubes would have a volume of 3 cubic units.

(D)Three of the one-third cubes will make 1 unit cube.

 3*\frac{1}{3} =1$ cubic units

(E)Two of the one-half cubes will make 1 unit cube.

 2*\frac{1}{2} =1$ cubic units

(F)Both stacks will have a volume of 3 cubic units.

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Step-by-step explanation:

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<em>Comment on the problem</em>

This is equivalent to asking, "where do I place a mirror on the ground so I can see the top of the other pole by looking in the mirror from the top of one pole?" Such a question is answered by reflecting one pole across the plane of the ground and drawing a straight line from its image location to the top of the other pole. Where the line intersects the plane of the ground is where the mirror (or anchor point) should be placed. The "similar triangle" description above is essentially the same approach.

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