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VashaNatasha [74]
4 years ago
7

why would you predict that females in species with internal fertilization and long periods of gestation would be choosier in sel

ecting their males than females in other species
Biology
1 answer:
nevsk [136]4 years ago
5 0

Im not sure but i did find this answer: patient is most likely to be suffering from diabetic nephropathy.

Explanation:

Three major histological changes occur in the glomeruli of pateints with diabetic nephropathy. First, mesangial expansion is directly induced by hyperglycaemia, possibly through increased matrix production or glycation of matrix proteins. Second, thickening of the glomerular basement membrane (GBM). Third, glomerular sclerosis is caused by intraglomerular hypertension (brought by dilatation of the afferent renal artery or from ischemic injury induced by hyaline narrowing of the vessels supplying the glomeruli).  The important change in diabetic glomerulopathy is increase of extracellular matrix. The earliest morphological anomaly in diabetic nephropathy is the thickening of the glomerular basement membrane and expansion of the mesangium due to the accumulation of extracellular matrix.

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In a population of cats, the phenotypic frequency of black cats is 91%, and the phenotypic frequency of white cats is 9%. Assumi
Talja [164]

Answer:

1. Allele frequency of b = 0.09 (or 9%)

2. Allele frequency of B = 0.91 (0.91%)

3. Genotype frequency of BB = 0.8281 (or 82.81%)

4. Genotype frequency of Bb = 0.1638 (or 16.38%)

Explanation:

Given that:

p = the frequency of the dominant allele (represented here by B)  = 0.91

q = the frequency of the recessive allele (represented here by b)  = 0.09

For a population in genetic equilibrium:

p + q = 1.0 (The sum of the frequencies of both alleles is 100%.)

(p + q)^2 = 1

Therefore:

p^2 + 2pq + q^2 = 1

in which:  

p^2 = frequency of BB (homozygous dominant)

2pq = frequency of Bb (heterozygous)

q^2 = frequency of bb (homozygous recessive)

p^2 = 0.91^2 = 0.8281

2pq = 2(0.91)(0.9) = 0.1638

4 0
3 years ago
What does a S-shaped curve demonstrate for population growth?
11111nata11111 [884]

A design of growth in which (occurs only in a different situation), the population frequency of an organism rises gradually originally, in a good acceleration time, later progresses swiftly nearing an exponential growth pace just like the J-shaped curve, however, it later declines (meaning rejects) in a bad acceleration time till at zero growth rate the population maintains. For example, yeast is a tiny fungus, so tiny, a microscope is required to view it, furthermore, it is used to produce bread and alcoholic drinks, displays the traditional S-shaped curve if raised in a test tube. Its maturity levels off as the population deplete the nutrients that are essential for its growth.

7 0
3 years ago
Sitting in front of a computer for a long time can lead to which physical disorder?
astraxan [27]
Eye strain - hope this helped
3 0
3 years ago
Animals which have the ability to determine the survivability of other
kramer

Answer:

scientist has brought together all the research on the subject and found that, from bees to birds to wolves, many animals have an ability to process and represent numbers arguably a form of counting.

Explanation: What's more, the new study suggests that this mathematical prowess helps animals stay alive in a brutal world. Such a finding extends our knowledge of animal cognition, a field that has grown exponentially in recent years.

8 0
3 years ago
The process in which the cell makes an exact<br> copy of the DNA in its nucleus
Virty [35]
This process of dna copying would be mitosis.
7 0
3 years ago
Read 2 more answers
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