A drone has an initial velocity of 38m/s. Five seconds later it reaches a velocity

Mathematics

1 answer:

timofeeve [1]3 years ago

7 0

Answer:

The acceleration of the drone is 2.6 m/s²

Step-by-step explanation:

The acceleration is the rate at which the speed changes over time, therefore to solve this question we must divide the change of speed by the elapsed time in order to find the accelaration of the drone in that period. We have:

a = (Vf - Vi)/dt

Where a is the acceleration, Vf is the final velocity, Vi is the initial velocity and dt is the elapsed time. We have:

a = (51 - 38)/5 = 2.6 m/s²

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Secants L J and L M intersect and form an angle at point L. Solve for x.

german

Answer:

x = 14

Step-by-step explanation:

Assume your diagram is like the one below.

The intersecting secant angles theorem states, "When two secants intersect outside a circle, the measure of the angle formed is one-half the difference between the far and the near arcs."

For your diagram, that means

$\begin{array}{rcl}m\angle L &=&\dfrac{1}{2} \left(m \widehat {JM} - m\widehat {PQ}\right)\\\\(3x + 13)^{\circ}& = &\dfrac{1}{2} \left[(8x + 48)^{\circ} - (5x - 20)^{\circ}\right]\\\\3x + 13& = &\dfrac{1}{2}(8x + 48 - 5x + 20)\\\\3x + 13& = &\dfrac{1}{2}(3x + 68)\\\\6x + 26 & = & 3x + 68\\6x & = & 3x + 42\\3x & = & 42\\x & = & \mathbf{14}\\\end{array}$

Check:

$\begin{array}{rcl}(3\times14 + 13) & = &\dfrac{1}{2} \left[(8\times14 + 48)^{\circ} - (5\times14 - 20)^{\circ}\right]\\\\42 + 13& = &\dfrac{1}{2}(112 + 48 - 70 + 20)\\\\55& = &\dfrac{1}{2}(110)\\\\55 & = & 55\\\end{array}$