Let x and y be the two numbers.
x = y - 4
2y = 5x - 10
solve the system of equations:
2y = 5(y - 4) - 10
2y = 5y - 20 - 10
-3y = -30
y = 10
x = 10 - 4 = 6
A is 0.0028
and B is 0.054
Answer:
a) 66
b) 45
Step-by-step explanation:
We have 12 horses and after the first race 2 of them have to be eliminated
that condition is equal to consider that 10 horses will be available for the second race.
The number of possiblities we have for the first race is the combination of 12 horses in group of 10
C¹²₁₀ = 12!/ (2!)* (12-2)! = 12*11/2 = 66
For the second race
C¹⁰₈ = 10! / 8! * (10-8)! = 10*9/ 2 = 45
Answer:
Step-by-step explanation:
i am not really fully sure
Step-by-step explanation:
2(x-3)=5(x-3)+10
=> 2x - 6 = 5x - 15 + 10
=> -6 + 15 -10 = 5x - 2x
=> 5x -2x = 15 - 6 - 10
=> 3x = 15 - 16
=> 3x = -1
