we'd do the same as before on this one as well.
if we take 27.99 to be the 100%, what is 12 off of it in percentage?
A family has two cars. The first car has a fuel efficiency of 40 miles per gallon of gas and the second has a fuel efficiency of
1 answer:
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Answer:
(a) The probability that only one goblet is a second among six randomly selected goblets is 0.3888.
(b) The probability that at least two goblet is a second among six randomly selected goblets is 0.1776.
(c) The probability that at most five must be selected to find four that are not seconds is 0.9453.
Step-by-step explanation:
Let <em>X</em> = number of seconds in the batch.
The probability of the random variable <em>X</em> is, <em>p</em> = 0.31.
The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>p</em>.
The probability mass function of <em>X</em> is:
(a)
Compute the probability that only one goblet is a second among six randomly selected goblets as follows:
Thus, the probability that only one goblet is a second among six randomly selected goblets is 0.3888.
(b)
Compute the probability that at least two goblet is a second among six randomly selected goblets as follows:
P (X ≥ 2) = 1 - P (X < 2)
Thus, the probability that at least two goblet is a second among six randomly selected goblets is 0.1776.
(c)
If goblets are examined one by one then to find four that are not seconds we need to select either 4 goblets that are not seconds or 5 goblets including only 1 second.
P (4 not seconds) = P (X = 0; n = 4) + P (X = 1; n = 5)
Thus, the probability that at most five must be selected to find four that are not seconds is 0.9453.
Answer:
The correct option is;
No, The greater rate of change of Plant A will result in it being 0.9 inches taller in 6 weeks
Step-by-step explanation:
The parameters given are;
Plant A:
Weeks, Height
0, 3
1, 4.8
2, 6.6
3, 8.4
The rate of change of height, H per week, t, for plant A per week is therefore;
Therefore we have;
H = 1.8 × t + 3
At week 6,
H = 3 + 6×1.8 = 13.8 inches
Plant B
Weeks, Height
2, 7.3
3, 8.7
4, 10.1
The rate of change of height, H per week, t, for plant B per week is given as follows;
Therefore we have;
When t = 2, H = 7.3 hence, 7.3 = 2 × 1.4 + H₀
Where:
H₀ = H at t = 0
H₀ = 7.3 - 2 × 1.4 = 4.5
At week 6 we have;
H = 4.5 + 6×1.4 = 12.9 inches
Which indicates that Plant A will be 0.9 inches taller than Plant B at week 6.
The correct option is therefore;
No, The greater rate of change of Plant A will result in it being 0.9 inches taller in 6 weeks.