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Slav-nsk [51]
3 years ago
12

How do you find a total resistance in physical science

Physics
1 answer:
BabaBlast [244]3 years ago
6 0

Add all of the resistances across the circuit together to calculate the total resistance. If you don't know the individual values, use the Ohm's Law equation, where resistance = voltage divided by current. Plug in the values for voltage and current and solve for R to get the total resistance in a circuit.

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A mass is stretched 4 centimeters from the equilibrium position of a spring. If the displacement is doubled, what can be conclud
marta [7]
From Simple Harmonic Motion (SHM),  the restoring force is given by:

   F  =  -ω²x

We can see that restoring force is proportional to the displacement, x. So if the displacement x is doubled, then the restoring force will also be doubled.
8 0
3 years ago
Read 2 more answers
a 5.0 kg ball is dropped from a 2.5 m high window. what is the velocity of the ball just before it hits the ground?
julsineya [31]

Answer:

Approximately 7.0\; \rm m \cdot s^{-1}.

Assumption: the ball dropped with no initial velocity, and that the air resistance on this ball is negligible.

Explanation:

Assume the air resistance on the ball is negligible. Because of gravity, the ball should accelerate downwards at a constant g = 9.81 \; \rm m \cdot s^{-2} near the surface of the earth.

For an object that is accelerating constantly,

v^2 - u^2 = 2\, a \, x,

where

  • u is the initial velocity of the object,
  • v is the final velocity of the object.
  • a is its acceleration, and
  • x is its displacement.

In this case, x is the same as the change in the ball's height: x = 2.5\; \rm m. By assumption, this ball was dropped with no initial velocity. As a result, u = 0. Since the ball is accelerating due to gravity, a = 9.81\; \rm m \cdot s^{-2}.

v^2 - u^2 = 2\, g \cdot h.

In this case, v would be the velocity of the ball just before it hits the ground. Solve for

v^2 = 2\, a\, x + u^2.

\begin{aligned}v &= \sqrt{2\, a\, x + u^2} \\ &= \sqrt{2\times 9.81 \times 2.5 + 0} \\ &\approx 7.0\; \rm m\cdot s^{-1}\end{aligned}.

3 0
3 years ago
3. What is the difference between an emission spectrum and an absorption spectrum? What is the Bohr model of the atom, and how d
pishuonlain [190]
The Bohr model resembles a planetary system in which the negatively-charged electrons orbit a small and very dense, positively-charged nucleus at the atom's center.
The electrons are held in orbit by the Coulomb (electrical) force between the positively-charged nucleus and the negatively-charged electrons.

The electrons cannot occupy just any orbital radius.
Only orbits with a very specific set of energy values are permitted (which all atoms of a given element have in common and are unique to that element).
The lowest energy (or ground state) corresponds to orbit closest to the nucleus and photons with specific amounts of electromagnetic radiation are absorbed or emitted when an electron moves from one orbit to another (absorbed to move further up the permitted levels and away from the nucleus)


An atomic line spectrum is the whole range of specific photon radiation frequencies that an element can emit or absorb as it's electrons move between the energy levels allowed in those atoms.

The emissions correspond with electrons descending 'down' their energy levels, with the energy differences being carried away by photons with the appropriate frequency. Consequently an emission spectra is a series of specific, single color lines (against a black background) for each of the emitted frequencies.

Photon absorption provides the energy for electrons to 'climb' the set of energy levels for that element. So, putting electrons into higher energy states within an atom.
When the absorbed photons are removed from incident light containing the full spectrum, their absence is seen as a series of fine black lines on an otherwise continuous spectrum background.

<span> The features in absorption and emission spectra coincide exactly for atoms of a given element. </span>
8 0
3 years ago
The first step in responding to any sports injury is to __________.
larisa86 [58]

Answer:

THE ANSWER IS..................................................... UHHHH IM JK ITS (A)

Explanation:

6 0
3 years ago
Read 2 more answers
A car is moving at a velocity of 25 km/h and increases velocity to 1200 km/h in 2 min. what is the acceleration?
OlgaM077 [116]

Answer:

a = 2.72 [m/s2]

Explanation:

To solve this problem we must use the following kinematics equation:

v_{f} =v_{o} + a*t

where:

Vf = final velocity = 1200 [km/h]

Vo = initial velocity = 25 [km/h]

t = time = 2 [min] = 2/60 = 0.0333 [h]

1200 = 25 + (a*0.0333)

a = 35250.35 [km/h2]

if we convert these units to units of meters per second squared

35250.35[\frac{km}{h^{2} }]*(\frac{1}{3600^{2} })*[\frac{h^{2} }{s^{2} } ]*(\frac{1000}{1} )*[\frac{m}{km} ] = 2.72 [\frac{m}{s^{2} } ]

3 0
3 years ago
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