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2 years ago

13

What is the answer to this question?

1 answer:

ziro4ka [17]2 years ago

5 0

The answer would be a.6

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3 years ago

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polet [3.4K]

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3 years ago

X^3-2x^2+5x-10=0<br> how do you solve or factor this polynomial?

pshichka [43]

$\bf x^3-2x^2+5x-10=0\implies \stackrel{\textit{doing some grouping}}{(x^3-2x^2)+(5x-10)}=0 \\\\\\ \stackrel{\textit{common factoring}}{x^2\underline{(x-2)}+5\underline{(x-2)}}=0\implies \stackrel{\textit{more common factoring}}{\underline{(x-2)}(x^2+5)}=0 \\\\[-0.35em] ~\dotfill\\\\ x-2=0\implies x=2~~~~\textit{\large\checkmark} \\\\[-0.35em] ~\dotfill\\\\ x^2+5=0\implies x^2=-5\implies x=\sqrt{-5}\implies x=i\sqrt{5}\quad \bigotimes$

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2 years ago

dezoksy [38]

Answer:

Answer 3 (-6x-2y=12)

Step-by-step explanation: Turn to slope form to check

First- Add the 6x from both sides

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Second- Divide by two on both sides

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