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maxonik [38]
3 years ago
15

Given the equation square root of quantity 3x plus 6 end quantity equals 3, solve for x and identify if it is an extraneous solu

tion. 1; solution is extraneous 1; solution is not extraneous 3; solution is extraneous 3; solution is not extraneous
Mathematics
1 answer:
Novay_Z [31]3 years ago
5 0

Solution is not extraneous, x=1 is correct answer

Step-by-step explanation:

We need to solve the equation \sqrt{3x+6}=3 and find value of x.

Solving:

\sqrt{3x+6}=3\\Taking\,\,square\,\,on\,\,both\,\,sides\\(\sqrt{3x+6})^2=(3)^2\\3x+6=9\\Simplifying:\\3x=9-6\\3x=3\\x=3/3\\x=1

So. Value of x = 1

Now checking if solution is extraneous or not

Solution is extraneous if value of x doesn't satisfy the given equation.

Checking: putting x=1 in the equation \sqrt{3x+6}=3

\sqrt{3x+6}=3\\\sqrt{3(1)+6}=3\\\sqrt{9}=3\\ 3=3

Since x=1, verifies the given equation so, x=1 is not extraneous solution

Solution is not extraneous, x=1 is correct answer

Keywords: Solving equations and finding extraneous roots

Learn more about Solving equations and finding extraneous roots at:

  • brainly.com/question/1626495
  • brainly.com/question/2959656
  • brainly.com/question/4046256

#learnwithBrainly

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