We need Pythagoras theorem here
a^2+b^2 = c^2
a, b = legs of a right-triangle
c = length of hypotenuse
Let S=shorter leg, in cm, then longer leg=S+2 cm
use Pythagoras theorem
S^2+(S+2)^2 = (10 cm)^2
expand (S+2)^2
S^2 + S^2+4S+4 = 100 cm^2 [collect terms and isolate]
2S^2+4S = 100-4 = 96 cm^2
simplify and form standard form of quadratic
S^2+2S-48=0
Solve by factoring
(S+8)(S-6) = 0 means (S+8)=0, S=-8
or (S-6)=0, S=6
Reject nengative root, so
Shorter leg = 6 cm
Longer leg = 6+2 cm = 8 cm
Hypotenuse (given) = 10 cm
Answer:
Step-by-step explanation:
The given sequence of numbers is increasing in geometric progression. The consecutive terms differ by a common ratio, r
Common ratio = 6/3 = 12/6 = 2
The formula for determining the nth term of a geometric progression is expressed as
Tn = ar^(n - 1)
Where
a represents the first term of the sequence.
r represents the common ratio.
n represents the number of terms.
From the information given,
a = 3
r = 2
The function, f(n), representing the nth term of the sequence is
f(n) = 3 × 2^(n - 1)
4:25
60 mins in 1 hour
4 hours after 4:25=8:25
45 mins+8:25
45+25=70
70=60+10
60=1 hour
add 1 to 8
9
9:10 am is the answer
