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soldier1979 [14.2K]
3 years ago
11

Find the sum of the first 9 terms in the following geometric series. 64+32+16...

Mathematics
2 answers:
dmitriy555 [2]3 years ago
7 0

The answer is attached.

Stolb23 [73]3 years ago
5 0

Answer:

127.75

Step-by-step explanation:

64+32+16+8+4+2+1+.5+.25=127.75

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1

Step-by-step explanation:

Anything to the power of 0 equals 1

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-4 &lt; - 13( a + 6) -1 7
krek1111 [17]

Answer:

-4 < -13(a+6)-17

-4<-13a+(-78)-17

-4<-13a+(-95)

-4<-13a-95

91<-13a

-91>13a

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Step-by-step explanation:

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3 years ago
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The head librarian at the Library of Congress has asked her assistant for an interval estimate of the mean number of books check
Verdich [7]

Answer:

n=(\frac{1.960(150)}{90})^2 =10.67 \approx 11

So the answer for this case would be n=11 rounded up to the nearest integer

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

\sigma =150 represent the population standard deviation

n represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

The confidence interval for this case is given by: (740, 920)

We can find the estimate for the mean and we got:

\bar X = \frac{740+920}{2} = 830

and the margin of error is given by :

ME = \frac{920-740}{2}= 90

The margin of error is given by this formula:

ME=z_{\alpha/2}\frac{s}{\sqrt{n}}    (a)

And on this case we have that ME =90 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

n=(\frac{z_{\alpha/2} s}{ME})^2   (b)

The critical value for 95% of confidence interval now can be founded using the normal distribution. And in excel we can use this formla to find it:"=-NORM.INV(0.025;0;1)", and we got z_{\alpha/2}=1.960, replacing into formula (b) we got:

n=(\frac{1.960(150)}{90})^2 =10.67 \approx 11

So the answer for this case would be n=11 rounded up to the nearest integer

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3 years ago
How many solutions can be found for the system of linear equations represented on the graph?
g100num [7]

Answer:

A) no solution

Step-by-step explanation:

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