The time required for one wing beat is 5 milliseconds.
<em><u>Explanation</u></em>
Lets assume, the time required for one wing beat is 
seconds
So, the time required for 200 wing beat 
seconds
Given that, the honeybee flaps its wings 200 times per 1 second. So...
So, the time required for one wing beat is 5 milliseconds.
Answer: 151
Step-by-step explanation:
12 x 13 = 156
156 - 5 = 151
Answer:
table f is the one that is proportional
Step-by-step explanation:
on the graph start at the origin (0,0) then go to the right once and then go up twice and place a point. Then go over once again and go up 2 lines again and place another. Repeat this process five times.
