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Sergio [31]
3 years ago
5

Can someone please tell me why I got this wrong?

Mathematics
1 answer:
kvasek [131]3 years ago
8 0
We have 
f(x)=<span>−x</span>²<span>+ 5x + 6
g(x)=</span><span>3x − 2

we know that
f(x)=g(x)
the solution is the intersection both graphs

using a graph tool
see the attached figure

the solution are the points
(4,10)
and
(-2,-8)

</span>

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If m^2 = 3 then what is the value of 5m^6<br><br> a. 15<br> b. 30<br> c. 45<br> d. 135
Virty [35]

Answer:

135

Step-by-step explanation:

m^2 = 3

Cube m^2

(m^2)^3 = 3^3

m^(2*3) = 27

m^6 = 27

Now multiply by 5

5 * m^6 = 5*27

5 m^6 =135

4 0
3 years ago
Defined by two lines or rays diverging from a common point.
kotykmax [81]
B. your answer is an angle
8 0
3 years ago
Read 2 more answers
Thank you very much for your help!
Kobotan [32]
For a.
x^2+y^2=25

For b.
(x-4)^2+(y-3)^2=25

For c.
(x-5)^2+(y-4)^2=9


Hope that helps
5 0
3 years ago
The lifespan (in days) of the common housefly is best modeled using a normal curve having mean 22 days and standard deviation 5.
Natasha_Volkova [10]

Answer:

Yes, it would be unusual.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

If Z \leq -2 or Z \geq 2, the outcome X is considered unusual.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question, we have that:

\mu = 22, \sigma = 5, n = 25, s = \frac{5}{\sqrt{25}} = 1

Would it be unusual for this sample mean to be less than 19 days?

We have to find Z when X = 19. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{19 - 22}{1}

Z = -3

Z = -3 \leq -2, so yes, the sample mean being less than 19 days would be considered an unusual outcome.

7 0
3 years ago
Express 500 g as a percentage of 2.5 kg.​
azamat

Answer:

500 grams is 20 percent of 2.5 kg

Step-by-step explanation:

500*100 = 50,000

50,000/2500=20

8 0
3 years ago
Read 2 more answers
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