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2 years ago

Find the midpoint of the line segment JK if j (4,6) and k(0,-4)

Mathematics

1 answer:

Snowcat [4.5K]2 years ago

4 0

Answer:

$(2,1)$

General Formulas and Concepts:

Order of Operations: BPEMDAS

Midpoint Formula: $(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})$

Step-by-step explanation:

Step 1: Define points

J (4, 6)

K (0, -4)

Step 2: Find midpoint

Substitute: $(\frac{4+0}{2},\frac{6-4}{2})$
Add/Subtract: $(\frac{4}{2},\frac{2}{2})$
Divide: $(2,1)$

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2 years ago

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DochEvi [55]

Answer:

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Step-by-step explanation:

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3 years ago

Applying properties of Exponents in exercise,use the properties of exponents to simplify the expression.See example 1.

evablogger [386]

Answer: a) 15625, b) 0.2, c) 625, d) 0.008.

Step-by-step explanation:

Since we have given that

a) $(5^2)(5^3)$

As we know that

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So, it becomes,

$5^2\times 5^3=5^{2+3}=5^6=15625$

(b) $(5^2)(5^{-3})$

So, it becomes,

$5^2\times 5^{-3}=5^{2-3}=5^{-1}=\dfrac{1}{5}=0.2$

As we know that

$(a^m)^n=a^{mn}$

So, it becomes,

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2 years ago

A farmer estimated that there were 25 gallons of water left in a tank. If this is an underestimate by 16%, how much water was ac

djyliett [7]

Answer:

The actual water in the tank is 29.76 gallons.

Step-by-step explanation:

It is given that the farmer estimated amount of water is 25 gallons.

It is also given that he underestimate the water in tank by 16%.

Let the actual water in tank be x.

$(1-\frac{16}{100})x=25$

$(\frac{100-16}{100})x=25$

$84x=25\times 100$

$x=\frac{2500}{84}$

$x=29.7619$

$x\approx 29.76$

Therefore the actual water in the tank is 29.76 gallons.

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3 years ago