Answer:
The answer is 364. There are 364 ways of choosing a recorder, a facilitator and a questioner froma club containing 14 members.
This is a Combination problem.
Combination is a branch of mathematics that deals with the problem relating to the number of iterations which allows one to select a sample of elements which we can term "<em>r</em>" from a collection or a group of distinct objects which we can name "<em>n</em>". The rules here are that replacements are not allowed and sample elements may be chosen in any order.
Step-by-step explanation:
Step I
The formula is given as
n (objects) = 14
r (sample) = 3
Step 2 - Insert Figures
C (14, 3) = =
=
=
= 364
Step 3
The total number of ways a recorder, a facilitator and a questioner can be chosen in a club containing 14 members therefore is 364.
Cheers!
It would be y=4x-2 because:
8x-3y=6-4x
-8x -8x
-3y=6-12x
/-3 /-3 /-3
y=-2+4x
y=4x-2
Answer:
$4.06
Step-by-step explanation:
23 / 5 = 4
Remainder = 3
$3 into dimes = 30 dimes
30 / 5 = 6
$4 + €6 = $4.06
Answer:
WHERE IS THE ANSWER
Step-by-step explanation:
Answer:
its c)
Step-by-step explanation:
just looked it up