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3 years ago

What is the domain of the function

Mathematics

2 answers:

Aleks [24]3 years ago

8 0

The answer would be x

koban [17]3 years ago

4 0

X is the domain of any function

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Which situation could be represented by the graph?

Y_Kistochka [10]

Answer:

A program at a community college can be completed in no fewer than 8 months, but must be completed in less than 11 months.

Step-by-step explanation:

1. The closed dot means the number is equal to and the open dot means the number is less/ greater than

2. The line goes right from the 8 with a closed dot, making x greater than or equal to 8

3. The line goes left from the 11 with an open dot, making x less than ll

4. This means the number must be equal to or greater than 8, and less than 11

9 0

3 years ago

Read 2 more answers

Can someone please help me I really need help

antoniya [11.8K]

It should be X < 25/52

4 0

3 years ago

Read 2 more answers

A jumping spider's movement is modeled by a parabola. The spider makes a single jump from the origin and reaches a maximum heigh

Stella [2.4K]

A parabola is a mirror-symmetrical U-shape.

The equation of the parabola is $\mathbf{y = -\frac{1}{640}(x - 80)^2 + 10}$
The focus is $\mathbf{Focus = (80, -1760)}$
The directrix is $\mathbf{y = \frac{1}{640}}$
The axis of the symmetry of parabola is: $\mathbf{x = 80}$

From the question, we have:

$\mathbf{Vertex: (h,k) = (80,10)}$

$\mathbf{Origin: (x,y) = (0,0)}$

The equation of a parabola is:

$\mathbf{y = a(x - h)^2 + k}$

Substitute the values of origin and vertex in $\mathbf{y = a(x - h)^2 + k}$

$\mathbf{0 = a(0 - 80)^2 + 10}$

$\mathbf{0 = a(- 80)^2 + 10}$

$\mathbf{0 = 6400a + 10}$

Collect like terms

$\mathbf{6400a =- 10}$

Solve for a

$\mathbf{a =- \frac{1}{640}}$

Substitute the values of a and the vertex in $\mathbf{y = a(x - h)^2 + k}$

$\mathbf{y = -\frac{1}{640}(x - 80)^2 + 10}$

The focus of a parabola is:

$\mathbf{Focus = (h, \frac{k+1}{4a})}$

Substitute the values of a and the vertex in $\mathbf{Focus = (h, \frac{k+1}{4a})}$

$\mathbf{Focus = (80, \frac{10+1}{4 \times -\frac{1}{640}})}$

$\mathbf{Focus = (80, -\frac{11}{\frac{1}{160}})}$

$\mathbf{Focus = (80, -11\times 160)}$

$\mathbf{Focus = (80, -1760)}$

The equation of the directrix is:

$\mathbf{y = -a}$

So, we have:

$\mathbf{y = \frac{1}{640}}$ ----- the directrix

The axis of symmetry is:

$\mathbf{x = -\frac{b}{2a}}$

We have:

$\mathbf{y = -\frac{1}{640}(x - 80)^2 + 10}$

Expand

$\mathbf{y = -\frac{1}{640}(x^2 -160x + 6400) +10}$

Expand

$\mathbf{y = -\frac{1}{640}x^2 +\frac{1}{4}x - 10 +10}$

$\mathbf{y = -\frac{1}{640}x^2 +\frac{1}{4}x }$

A quadratic function is represented as:

$\mathbf{y = ax^2 + bx + c}$

So, we have:

$\mathbf{a = -\frac{1}{640}}$

$\mathbf{b = \frac{1}{4}}$

Recall that:

$\mathbf{x = -\frac{b}{2a}}$

So, we have:

$\mathbf{x = -\frac{1/4}{2 \times -1/640}}$

$\mathbf{x = \frac{1/4}{1/320}}$

This gives

$\mathbf{x = \frac{320}{4}}$

$\mathbf{x = 80}$

Hence, the axis of the symmetry of parabola is: $\mathbf{x = 80}$

Read more about parabola at:

brainly.com/question/21685473

6 0

3 years ago

2. What is the sample proportion of heads in your sample of 40? Report this value to your teacher.

Alexeev081 [22]

Answer:

$\frac{18}{40}=0.45$

Though it may vary, it's going closer to 0.5 as long as we enlarge our sample.

Step-by-step explanation:

1) Since a coin has heads and tails, then a sample proportion of 40 we can simulate it using some applets.

2) Here are the most common outcomes, as long as we continue on flipping coins.

$\frac{18}{40}=0.45$

If we continue enlarging our sample (80, 120,160...) the probability goes closer to 0.5

This shows: the theoretical probability goes closer and closer to the experimental probability of heads and tails

$S_{80}=0.503\\S_{120}=0.50$

6 0

3 years ago

What would the answer be for this question to find out the answer to it

Kay [80]

Answer: 294

Step-by-step explanation:

81-25+800/2=

81-25+400=

81-375= 294

3 0

3 years ago