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TEA [102]
3 years ago
12

Two cylinders, A and B, are mathematically similar. The height of B is twice the corresponding height of A.
 The volume of A is

13 cm^3. Find the volume of B.
Mathematics
2 answers:
Korvikt [17]3 years ago
7 0

Answer:

104 cm^3

Step-by-step explanation:

The ratio of volumes is the cube of the ratio of linear dimensions for similar figures. Since the height of B is 2 times the height of A, the volume of B will be 2^3 = 8 times the volume of A, so is ...

8·13 cm^3 = 104 cm^3

tatuchka [14]3 years ago
5 0

Answer:

The volume of B is 39cm³

Step-by-step explanation:

Volume of cylinder A

Va = 1/3πr²ha ...(1)

Where height of A is ha

If the height of B is twice the corresponding height of A

hb = 3ha

Volume of B Vb = 1/3πr²(3ha)...(2)

If volume of A is 13cm³ and

Va = 1/3πr²ha

Then 13 = 1/3πr²ha

39 = πr²ha

πr² = 39/ha ... (3)

To get Vb, we wil substitute equation 3 into 2 to have;

Vb = 1/3(39/ha)(3ha)

Vb = 39/ha × ha

Vb = 39cm³

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2 years ago
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What are the factors of 2x^2 + 5x -12?
Andrews [41]

Answer:

(2x - 3) • (x + 4)

Step-by-step explanation:

Step  1  :

Equation at  step  1  :

 (2x2 +  5x) -  12

Step  2  :

Trying to factor by splitting the middle term

2.1     Factoring  2x2+5x-12  

The first term is,  2x2  its coefficient is  2 .

The middle term is,  +5x  its coefficient is  5 .

The last term, "the constant", is  -12  

Step-1 : Multiply the coefficient of the first term by the constant   2 • -12 = -24  

Step-2 : Find two factors of  -24  whose sum equals the coefficient of the middle term, which is   5 .

-24    +    1    =    -23  

     -12    +    2    =    -10  

     -8    +    3    =    -5  

     -6    +    4    =    -2  

     -4    +    6    =    2  

     -3    +    8    =    5

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above,  -3  and  8  

                    2x2 - 3x + 8x - 12

Step-4 : Add up the first 2 terms, pulling out like factors :

                   x • (2x-3)

             Add up the last 2 terms, pulling out common factors :

                   4 • (2x-3)

Step-5 : Add up the four terms of step 4 :

                   (x+4)  •  (2x-3)

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3 years ago
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6 0
3 years ago
Twenty-four distinguishable balls are to be placed in six boxes.(DIFFERENT BOXES) (a) In how many different ways can this be don
zvonat [6]

Answer: a) 124,596, b) 2142691552.

Step-by-step explanation:

Since we have given that

Number of distinguishable balls = 24

Number of boxes = 6

(a) In how many different ways can this be done?

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(b) In how many different ways can this be done if box 1 must get 12 balls, box 2 must get 7 balls, box 3 must get 5 balls, and boxes 4, 5, and 6 must be empty?

Number of ways would be

\dfrac{24!}{12!7!5!}=2142691552

Hence, a) 124,596, b) 2142691552.

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Step-by-step explanation:

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