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NARA [144]
2 years ago
14

Please help! Will give brainiest!! Apply the distributive property to factor out the greatest common factor. 24+28=

Mathematics
1 answer:
alukav5142 [94]2 years ago
5 0

✧・゚: *✧・゚:*    *:・゚✧*:・゚✧

                  Hello!

✧・゚: *✧・゚:*    *:・゚✧*:・゚✧

❖ The GCF between 24 and 28 would be 4. To show this in distributive property, you would write it like this:

4(6+7)

24/4 is 6 and 28/4 is 7 so those are the two values you would put in parentheses.

~ ʜᴏᴘᴇ ᴛʜɪꜱ ʜᴇʟᴘꜱ! :) ♡

~ ᴄʟᴏᴜᴛᴀɴꜱᴡᴇʀꜱ

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The U.S. government has devoted considerable funding to missile defense research over the past 20 years. The latest development
Bad White [126]

Answer:

a) Let the random variable X= "number of these tracks where SBIRS detects the object." in order to use the binomial probability distribution we need to satisfy some conditions:

1) Independence between the trials (satisfied)

2) A value of n fixed , for this case is 20 (satisfied)

3) Probability of success p =0.2 fixed (Satisfied)

So then we have all the conditions and we can assume that:

X \sim Bin(n =20, p=0.8)

b) X \sim Bin(n =20, p=0.8)

c) P(X=15)=(20C15)(0.8)^{15} (1-0.8)^{20-15}=0.17456

d) P(X \geq 15) = P(X=15)+ .....+P(X=20)

P(X=15)=(20C15)(0.8)^{15} (1-0.8)^{20-15}=0.17456

P(X=16)=(20C16)(0.8)^{16} (1-0.8)^{20-16}=0.218

P(X=17)=(20C17)(0.8)^{17} (1-0.8)^{20-17}=0.205

P(X=18)=(20C18)(0.8)^{18} (1-0.8)^{20-18}=0.137

P(X=19)=(20C19)(0.8)^{19} (1-0.8)^{20-19}=0.058

P(X=20)=(20C20)(0.8)^{20} (1-0.8)^{20-20}=0.012

P(X\geq 15)=0.804208

e) E(X) = np = 20*0.8 = 16

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

The probability mass function for the Binomial distribution is given as:

P(X)=(nCx)(p)^x (1-p)^{n-x}

Where (nCx) means combinatory and it's given by this formula:

nCx=\frac{n!}{(n-x)! x!}

Part a

Let the random variable X= "number of these tracks where SBIRS detects the object." in order to use the binomial probability distribution we need to satisfy some conditions:

1) Independence between the trials (satisfied)

2) A value of n fixed , for this case is 20 (satisfied)

3) Probability of success p =0.2 fixed (Satisfied)

So then we have all the conditions and we can assume that:

X \sim Bin(n =20, p=0.8)

Part b

X \sim Bin(n =20, p=0.8)

Part c

For this case we just need to replace into the mass function and we got:

P(X=15)=(20C15)(0.8)^{15} (1-0.8)^{20-15}=0.17456

Part d

For this case we want this probability: P(X\geq 15)

And we can solve this using the complement rule:

P(X \geq 15) = P(X=15)+ .....+P(X=20)

P(X=15)=(20C15)(0.8)^{15} (1-0.8)^{20-15}=0.17456

P(X=16)=(20C16)(0.8)^{16} (1-0.8)^{20-16}=0.218

P(X=17)=(20C17)(0.8)^{17} (1-0.8)^{20-17}=0.205

P(X=18)=(20C18)(0.8)^{18} (1-0.8)^{20-18}=0.137

P(X=19)=(20C19)(0.8)^{19} (1-0.8)^{20-19}=0.058

P(X=20)=(20C20)(0.8)^{20} (1-0.8)^{20-20}=0.012

P(X\geq 15)=0.804208

Part e

The expected value is given by:

E(X) = np = 20*0.8 = 16

5 0
3 years ago
Katlyn made 4 dresses with 7 yards of fabric. How many yards did she use on 1 dress?
Murrr4er [49]

Answer:

the answer would be 1.75 or 1 3/4

Step-by-step explanation:


5 0
3 years ago
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The average cost of tuition, room and board at small private liberal arts colleges is reported to be $8,500 per term, but a fina
Vlada [557]

Answer:

The test statistic for this test is 3.82.

Step-by-step explanation:

The null hypothesis is:

H_{0} = 8500

The alternate hypotesis is:

H_{1} > 8500

Our test statistic is:

t = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation of the population and n is the size of the sample.

In this question:

X = 8745, \mu = 8500, \sigma = 1200, n = 350

So

t = \frac{8745 - 8500}{\frac{1200}{\sqrt{350}}} = 3.82

The test statistic for this test is 3.82.

5 0
3 years ago
3. Find the value of x. 4 3 6<br>​
tester [92]

Answer:

72

Step-by-step explanation:

x in (-oo:+oo)

(x/4)/3 = 6 // - 6

(x/4)/3-6 = 0

1/12*x-6 = 0 // + 6

1/12*x = 6 // : 1/12

x = 6/1/12

x = 72

x = 72

5 0
2 years ago
5/ 2 x ≤ -14<br><br> A. -10.3<br> B. -6<br> C. -5.6<br> D. -5
Advocard [28]

Answer:

C

Step-by-step explanation:

5/2x<_-14

5x<_-28

5x/5<_-28/6

X<_-5.6

4 0
2 years ago
Read 2 more answers
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