Solve it like a normal quadratic equation and take the root of the roots
x^4 + 10x^2 + 25 = 0
Δ = b² - 4.a.c
Δ = 10² - 4 . 1 . 25
Δ = 100 - 4. 1 . 25
Δ = 0
1 real root.
In this case, x' = x'':
x = (-b +- √Δ)/2a
x' = (-10 + √0)/2.1
x'' = (-10 - √0)/2.1
x' = -10 / 2
x'' = -10 / 2
x' = -5
x'' = -5
Now take the root of this roots
√-5 = i√5
The root of this equation is x = ±i√5
<span>Let the smallest of the three odd integer be A. The next integer will be (A+2), and the largest of the three is (A+4)
Given: A + (A+2) + (A+4) = 123
Combine like terms and solve for A as follows
3A + 6 = 123</span><span>Subtract 6 from each side of the equation to yield
3A = 117
Divide both sides by 3. Yields
A = 39
</span><span>The sum of three consecutive odd integers is 123. Fd the integers.
----------------
1st: 2n+1
2nd: 2n+3
3rd: 2n+5
-----------------
EQUATION:
2n+1 + 2n+3 + 2n+5 = </span><span>6n + 9 = 123
6n = 114
n = 19
-------------
1st: 2*19+1 = 39
2nd: 41
3rd: 43</span>
Answer:
115.2
Step-by-step explanation:
First we make an equation and replace blank with x.
Look at photos to see solution.
The key to solving this is to look at the 24 and the 28. First, look at option <span>A.4:74:7
To have 28 equal to 7, you need to divide by 4. But 24 divided by 4 equal 6, so option A doesn't work.
Option B, </span><span>12:1612:16. To have 24 equal to 12, divide by 2. But 28 divided by 2 is 14, not 16. Option B doesn't work either.
Now Option D. </span><span>48:5848:58 To have 24 equal to 48, multiply by 2. But 28 multiplied by 2 is 56, not 58. Option D does not work.
This only leaves option C.</span>
