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patriot [66]
3 years ago
6

What is the solution to (-4a^2)(2a^-3)^-4

Mathematics
1 answer:
ivann1987 [24]3 years ago
6 0

Answer:its -8a^-4

Step-by-step explanation:

multiply whats in the parenthesis first bc pemdas by foiling and then multiply the exponent when foiling you add the exponents so its 1 then 1 times -4 is -4 so it goes to -8a ^-4 and -8 bc -4 times 2

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A travels at an average speed of 55 miles per hour on the highway. Once inside the city limits, the truck decreases its speed by
Finger [1]
Answer:33mph
Step-by-step explanation:
the speed decrease by 40%
Therefore, (100-40)%*55miles/h
60%*55
0.6*55
33mph
6 0
3 years ago
Read 2 more answers
The floor of a rectangular deck has an area of 600 sq. ft. The floor is 20 ft. wide. How long is the floor?
grin007 [14]
<span>The question is asking us to determine the length of the floor of a rectangular deck. The rectangular deck has an area of 600 squared feet. The floor is 20 feet wide ( W = 20 ft ). Formula for the area of the rectangle is: A = L x W. 600 = L X 20; L = 600 : 20; L = 30 ft. Answer: The floor is 30 ft long.</span>
3 0
3 years ago
Andries get grandfather get offered to give him a gift of 50% of the amount of money he saved in one year. And Ray saved $120. H
sertanlavr [38]

Answer:

$60

Step-by-step explanation:

The savings of Andries is $120 and his grandfather offered that he would give 50% of the amount he saved.

50% is actually just half of a given amount.  So the short way to do this is just half the saving of Andries.

\dfrac{\$120}{2} = \$60

You can also think of it this way:

50\%=\dfrac{50}{100}

So we multiply that to the amount saved to solve for what is 50% of 120.

\$120\times\dfrac{50}{100} = \dfrac{\$6000}{100}=\$60.00

7 0
4 years ago
Solve the initial value problems:<br> 1/θ(dy/dθ) = ysinθ/(y^2 + 1); subject to y(pi) = 1
ladessa [460]

Answer:

-\theta cos\thsta+sin\theta = \frac{y^{2} }{2} + ln y + \pi  - \frac{1}{2}

Step-by-step explanation:

Given the initial value problem \frac{1}{\theta}(\frac{dy}{d\theta} ) =\frac{ ysin\theta}{y^{2}+1 } \\ subject to y(π) = 1. To solve this we will use the variable separable method.

Step 1: Separate the variables;

\frac{1}{\theta}(\frac{dy}{d\theta} ) =\frac{ ysin\theta}{y^{2}+1 } \\\frac{1}{\theta}(\frac{dy}{sin\theta d\theta} ) =\frac{ y}{y^{2}+1 } \\\frac{1}{\theta}(\frac{1}{sin\theta d\theta} ) = \frac{ y}{dy(y^{2}+1 )} \\\\\theta sin\theta d\theta = \frac{ (y^{2}+1)dy}{y} \\integrating\ both \ sides\\\int\limits \theta sin\theta d\theta =\int\limits  \frac{ (y^{2}+1)dy}{y} \\-\theta cos\theta - \int\limits (-cos\theta)d\theta = \int\limits ydy + \int\limits \frac{dy}{y}

-\theta cos\thsta+sin\theta = \frac{y^{2} }{2} + ln y +C\\Given \ the\ condition\ y(\pi ) = 1\\-\pi cos\pi +sin\pi  = \frac{1^{2} }{2} + ln 1 +C\\\\\pi + 0 = \frac{1}{2}+ C \\C = \pi  - \frac{1}{2}

The solution to the initial value problem will be;

-\theta cos\thsta+sin\theta = \frac{y^{2} }{2} + ln y + \pi  - \frac{1}{2}

5 0
3 years ago
Need help with solving a problem with elimination method
iren2701 [21]
Yes 7x+2x=35 that’s the problem I need help with
4 0
4 years ago
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