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Veseljchak [2.6K]
3 years ago
12

Which equation shows the variable terms isolated on one side and the constant terms isolated on the other side for the equation

3X -5 equals negative 2X +10
Mathematics
1 answer:
Andrej [43]3 years ago
3 0

Answer:

5x= 15

Step-by-step explanation:

Given

3x - 5 = -2x  +10

Required

Write the variables and constants on different sides

3x - 5 = -2x  +10

Add 2x to both sides

2x + 3x - 5 =2x -2x  +10

5x - 5 =10

Add 5 to both sides

5x - 5 + 5 = 10 + 5

5x= 10 + 5

5x= 15

Hence, the equation is

5x= 15

Solving further [divide both sides by 5]

x = 3

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Find the midpoint M of the line segment joining the points A = (-5, 7) and B = (-1, -5).
11111nata11111 [884]

Answer:

M = (-3,1)

Step-by-step explanation:

We need to find the midpoint M of the line segment joining the points

A = (-5,7) and B = (-1, -5)

The mid point of the line segment joining the points (x₁,y₁) and (x₂,y₂) is given by :

M=(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2})\\\\M=(\dfrac{-5+(-1)}{2},\dfrac{7+(-5)}{2})\\\\M=(-3,1)

Hence, the required point is (-3,1).

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What is the answer to f/2 =5/8
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Find the values of x and y if (-x + 5, 1) = (-y, 2x - 5y).
MrMuchimi

Answer:

x = 8, y = 3

Step-by-step explanation:

Equating corresponding x and y coordinates , then

- y = - x + 5 ( multiply through by - 1 )

y = x - 5 → (1)

2x - 5y = 1 → (2)

Substitute y = x - 5 into (2)

2x - 5(x - 5) = 1 ← distribute and simplify left side

2x - 5x + 25 = 1

- 3x + 25 = 1 ( subtract 25 from both sides )

- 3x = - 24 ( divide both sides by - 3 )

x = 8

Substitute x = 8 into (1) for corresponding value of y

y = 8 - 5 = 3

7 0
2 years ago
If the cos of angle x is 8 over 17 and the triangle was dilated to be two times as big as the original, what would be the value
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Answer:

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Step-by-step explanation:

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3 years ago
given the vector v has an initial point (-2,-6) and a terminal point of (1,2) write vector v as a linear combination of the stan
Anuta_ua [19.1K]

Answer:

v=3i+8j

Step-by-step explanation:

The given the vector v has an initial point (-2,-6) and a terminal point of (1,2).

To find the components of vector v, we subtract the terminal points from the initial point to obtain.

v=<1,2>-<-2,-6>

v=<1--2,2--6>

v=<1+2,2+6>

v=<3,8>

As a linear combination of the standard unit vectors.

v=3i+8j

7 0
3 years ago
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