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3 years ago

The manager determined that 35% of the shoes were sneakers. What simplified fractions of the shoes were sneakers

1 answer:

6 0

Percent is out of 100. By determining this, we figure that 35/100 would be the fraction you’d start with. To simplify, we divide them by the same numbers to get whole numbers. If you divide both by 5 (35÷5=7 and 100÷5=20), you’d get 7/20. This is the simplest form of the fraction.

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Find the exact sum of the arithmetic series 6+3.8+⋯−29.2

matrenka [14]

Answer:

-197.2

Step-by-step explanation:

Since it is arithmetic series, first find the difference d between the two know series.

3.8 - 6 = - 2.2

d = -2.2

a = 6

Tn = -29.2

Looking for the n term, use the linear method.

Tn = a+( n - 1)d

Substitute all the parameters

-29.2 = 6+( n - 1 ) -2.2

-29.2 = 6 - 2.2n + 2.2

- 29.2 = 8.2 - 2.2n

-29.2 - 8.2 = - 2.2n

-37.4 = -2.2n

n = 37.4/ 2.2

n = 17 terms.

To Find the exact sum of the arithmetic series, use the sum formula below

Sm = n/2( 2a + (n - 1)d)

Sm = 17/2( 2 × 6 + ( 17 - 1 ) -2.2

Sm = 17/2(12 - 35.2)

Sm = 8.5( - 23.2)

Sm = - 197.2

Therefore, the exact sum of the arithmetic series is -197.2

5 0

4 years ago

a five-card hand is dealt at random from a standard deck. What is the probability that the hand contains exactly two black cards

mestny [16]

Using the principle of binomial probability, the probability of having exactly two black cards is 0.3125

Probability of having a black card = 26/52 = 1/2

Using the binomial probability relation :

P(x = x) = nCx * p^x * q^(n-x)
p = probability of success = 1/2 = 0.5
Number of picks, n = 5
q = 1 - p = 0.5
x = 2

Hence,

P(x = 2) = 5C2 × 0.5² × 0.5³

P(x = 2) = 10 × 0.25 × 0.125

P(x = 2) = 0.3125

Hence. Probability of having exactly 2 black cards is 0.3125

Learn more : brainly.com/question/12474772

6 0

3 years ago

If G^-1(x) is the inverse of G(x), what is the value of G^-1(G(x))?

Ber [7]

Answer:

$G^{-1}(G(x))=x$

Step-by-step explanation:

Definition: Let f be one-to-one function with the domain A and the range B. Then the inverse function $f^{-1}$ has the domain B and the range A and is defined as