3 years ago

Please help me ! thank you

Mathematics

1 answer:

Tpy6a [65]3 years ago

4 0

1/2^-2 Can be written as 2^2

Therefore , 2×2=4

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mel-nik [20]

Answer:

0.018 is the required probability.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 60,000 miles

Standard Deviation, σ = 1500 miles

We are given that the distribution of tread life is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

P(brand will last between 56,850 miles and 57,300 miles)

$P(56850 \leq x \leq 57300) = P(\displaystyle\frac{56850 - 60000}{1500} \leq z \leq \displaystyle\frac{57300-60000}{1500}) = P(-2.1 \leq z \leq -1.8)\\\\= P(z \leq -1.8) - P(z < -2.1)\\= 0.0359 - 0.0179 = 0.018= 1.8\%$

$P(56850 \leq x \leq 57300) = 1.8\%$

0.018 is the probability a certain tire of this brand will last between 56,850 miles and 57,300 miles.

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Aneli [31]

79 would be the right answers

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Misha Larkins [42]

Answer:

x= 13, angle 1= 37, and angle 2= 53

Step-by-step explanation:

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