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Number of gallons of gas. Miles driven 0 0 2 62 4 124 10 310 How many gallons are used when the car has been driven 18 miles

Goryan [66]

558 gallons are used when the car has been driven 18 miles.

Step-by-step explanation:

From the given data, it can be determined that :

The number of gallons for 2 miles = 62 gallons
The number of gallons for 4 miles = 124 gallons
The number of gallons for 10 miles = 310 gallons

Let, the number of gallons for 18 miles = 'x' gallons

To find x :

compare the given data with the unknown data,

62 gallons / 2 miles = x gallons / 18 miles

keep x alone on one side,

x = (62×18) / 2

x = 31×18

x = 558 gallons

Therefore, 558 gallons are used to drive 18 miles.

3 0

3 years ago

I need help please?!!!!

Nata [24]

You would simply add the 54 to the -12 and get +42

3 0

3 years ago

Read 2 more answers

NEED ASAP!!!!!!!!!!!!. Multiply and express the result in scientific notation:

Snezhnost [94]

Your answer is 8.4 X 10^7.

Hope this helped!

4 0

3 years ago

Which of the following is a composite number that is divisible by both 3 and 5?A.116B.135C.1025D.1546

BlackZzzverrR [31]

The answer is B. 135.

6 0

3 years ago

The polynomial p(x)=3x^3-20x^2+37x-20 has a known factor of (x-4). Rewrite p(x) as a product of linear factors. p(x) =

vesna_86 [32]

Answer:

$p(x) = (3x^{2} - 8x + 5)(x - 4)$

Step-by-step explanation:

p(x) has degree 3

(x - 4) has degree 1

So p(x) can be rewritten as a polynomial of degree 2 multiplying (x-4)

So

$p(x) = (ax^{2} + bx + c)(x - 4)$

To find a, b and c, we have to divide p(x) by x - 4.

So

Finding a:

Dividing the first term of p(x) by x - 4.

$\frac{3x^{3}}{x - 4} = 3x^{2}$

So a = 3.

Now multiplying 3x² by, x - 4, we have:

$3x^{2}(x - 4) = 3x^{3} - 12x^{2}$

Subtracting p(x) from this:

$3x^{3} - 20x^{2} + 37x - 20 - (3x^{3} - 12x^{2}) = 3x^{3} - 20x^{2} + 37x - 20 - 3x^{3} + 12x^{2} = -8x^{2} + 37x - 20$

Finding b:

Dividing the first term, after the subtraction, by x - 4.

$\frac{-8x^{2}}{x - 4} = -8x$

So b = -8.

Multiplying -8x by x - 4, we have:

$-8x(x-4) = -8x^{2} + 32x$

Then

$-8x^{2} + 37x - 20 - (-8x^{2} + 32x) = -8x^{2} + 37x - 20 + 8x^{2} - 32x = 5x - 20$

Finding c:

$\frac{5x}{x - 4} = 5$

So c = 5.

Just to verify if the remainder is 0.

$5(x - 4) = 5x - 20$

$5x - 20 - (5x - 20) = 0$

Ok

Then:

$p(x) = (ax^{2} + bx + c)(x - 4)$

$p(x) = (3x^{2} - 8x + 5)(x - 4)$

7 0

3 years ago