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vaieri [72.5K]
3 years ago
8

PLEASE HELP! BRAINLIEST! So desperate.

Mathematics
1 answer:
PSYCHO15rus [73]3 years ago
8 0

Answer:

<B = 15

Step-by-step explanation:

A triangle adds up to 180 degrees.

Since these triangles are similar, the sides are located in the same spot. (A is in same spot as D, etc.)

A=75

F=90

75 + 90 + x = 180

165 + x = 180

x = 15

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40 sets of tires. I learned this by looking up your question because it is incomplete.
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3 years ago
Determine the asymptotes of the function graphed below.
bagirrra123 [75]

Answer:

C

Step-by-step explanation:

Asymptote is basically a line that the graph approaches but NEVER cuts/crosses.

<em><u>Remember, x = a where a is a constant is an equation of a vertical line and x = b, where b is a constant, is the equation of a horizontal line.</u></em>

<em><u /></em>

  • Looking at the graph, we can see that the curve doesn't cross an imaginary line at  x = 0, this is a vertical asymptote.
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Looking at the answer choices, the choice C is right.

3 0
3 years ago
PLEASEEE ITS EASY ALGEBRA 1 ):
Naya [18.7K]

Answer:

6, 7, and 8

Step-by-step explanation:

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Subtract 7 from both sides

2x/3 <u>></u> 4

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2x <u>></u> 12

Divide both sides by 2

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5 0
2 years ago
If a polynomial function f(x) has roots -8, 1, and 6i, what must also be a root of f(x)?
Naddik [55]

Answer:

it must also have the root : - 6i

Step-by-step explanation:

If a polynomial is expressed with real coefficients (which must be the case if it is a function f(x) in the Real coordinate system), then if it has a complex root "a+bi", it must also have for root the conjugate of that complex root.

This is because in order to render a polynomial with Real coefficients, the binomial factor  (x - (a+bi)) originated using the complex root would be able to eliminate the imaginary unit, only when multiplied by the binomial factor generated by its conjugate: (x - (a-bi)). This is shown below:

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where the imaginary unit has disappeared, making the expression real.

So in our case, a+bi is -6i (real part a=0, and imaginary part b=-6)

Then, the conjugate of this root would be: +6i, giving us the other complex root that also may be present in the real polynomial we are dealing with.

5 0
3 years ago
Translate the sentence into an equation. Five more than the product of a number and 9 is equal to 6
kap26 [50]
The first thing we will do for this case is to define the following variable:
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An equation for the sentence is:
 
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6 0
3 years ago
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