Answer by JKismyhusbandbae:
|x| - 2 > 0
|x| -2 + 2 > 0 + 2
|x| > 2
Answer: x < - 2 or x > 2
Answer:
=51.63 m^2
Step-by-step explanation:
First find the area of the triangle
A = 1/2 bh = 1/2(3) * 5 = 7.5
Then find the area of the rectangle
A = l*w = 5*6 = 30
Then find the area of the semi circle, which is 1/2 the area of the circle
The diameter is 6 so the radius is 3
A = 1/2 pi r^2 = 1/2 (3.14) (3) ^2 = 14.13
Add the areas together for the total area
7.5+30+14.13
=51.63
D. x+ 40 = 150 this is the answer
−8x + 4y = 24 -- (1)
−7x + 7y = 28 -- (2)
Eqn (1) & (2) are simplified as
y - 2x = 6 -- (3)
y - x = 4 -- (4)
By making y the subject of formula in (4), we have
y = x + 4 -- (5)
Substitute x + 4 for y in (3), then
x + 4 - 2x = 6
x - 2x = 6 - 4
- x = 2
x = - 2.
Substitute - 2 for x in (5), then
y = - 2 + 4
y = 2.
Therefore, (x, y) = (- 2, 2) ...Ans.
Given the function :
![f(x)=\sqrt[]{x+2}+1](https://tex.z-dn.net/?f=f%28x%29%3D%5Csqrt%5B%5D%7Bx%2B2%7D%2B1)
We need to find each missing value
Given x = -3 , -2 , -1 , 2 , 7
So, substitute with each value of x to find the corresponding value of f(x)
![x=-3\rightarrow f(x)=\sqrt[]{-3+2}+1=\sqrt[]{-1}+1](https://tex.z-dn.net/?f=x%3D-3%5Crightarrow%20f%28x%29%3D%5Csqrt%5B%5D%7B-3%2B2%7D%2B1%3D%5Csqrt%5B%5D%7B-1%7D%2B1)
So, there is no value for f(x) at x = -3 (the function undefined because the square root of -1)
![\begin{gathered} x=-2\rightarrow f(x)=\sqrt[]{-2+2}+1=\sqrt[]{0}+1=0+1=1 \\ \\ x=-1\rightarrow f(x)=\sqrt[]{-1+2}+1=\sqrt[]{1}+1=1+1=2 \\ \\ x=2\rightarrow f(x)=\sqrt[]{2+2}+1=\sqrt[]{4}+1=2+1=3 \\ \\ x=7\rightarrow f(x)=\sqrt[]{7+2}+1=\sqrt[]{9}+1=3+1=4 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20x%3D-2%5Crightarrow%20f%28x%29%3D%5Csqrt%5B%5D%7B-2%2B2%7D%2B1%3D%5Csqrt%5B%5D%7B0%7D%2B1%3D0%2B1%3D1%20%5C%5C%20%20%5C%5C%20x%3D-1%5Crightarrow%20f%28x%29%3D%5Csqrt%5B%5D%7B-1%2B2%7D%2B1%3D%5Csqrt%5B%5D%7B1%7D%2B1%3D1%2B1%3D2%20%5C%5C%20%20%5C%5C%20x%3D2%5Crightarrow%20f%28x%29%3D%5Csqrt%5B%5D%7B2%2B2%7D%2B1%3D%5Csqrt%5B%5D%7B4%7D%2B1%3D2%2B1%3D3%20%5C%5C%20%20%5C%5C%20x%3D7%5Crightarrow%20f%28x%29%3D%5Csqrt%5B%5D%7B7%2B2%7D%2B1%3D%5Csqrt%5B%5D%7B9%7D%2B1%3D3%2B1%3D4%20%5Cend%7Bgathered%7D)
the graph of the function and the points will be as shown in the following image :
