Question

What are the solution(s) to the quadratic equation 50 – x2 = 0? x = ±2Plus or minus 2 StartRoot 5 EndRoot x = ±6Plus or minus 6 StartRoot 3 EndRoot x = ±5Plus or minus 5 StartRoot 2 EndRoot no real solution

Answer 1

Answer:

Option 4 -  $x=\pm5\sqrt{2}$

Step-by-step explanation:

Given : Quadratic equation $50-x^2=0$

To find : What are the solution(s) to the quadratic equation ?

Solution :

Step 1 - Write the quadratic equation,

$50-x^2=0$

Step 2 - Subtract 50 both side,

$x^2=50$

Step 3 - Taking root both side,

$x=\pm\sqrt{50}$

$x=\pm\sqrt{2\times 5\times5}$

$x=\pm5\sqrt{2}$

Therefore, the solution of the equation is $x=\pm5\sqrt{2}$

So, option 4 is correct.

Answer 2

Answer:

C) x = ±5Plus or minus 5 StartRoot 2 EndRoot on ed!!!

Step-by-step explanation: