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salantis [7]
4 years ago
15

Math question...?

Mathematics
1 answer:
hoa [83]4 years ago
3 0
We have \sqrt{x}  \ \textless \  16 ;; where x >= 0;
Then, ( \sqrt{x}) ^{2} \ \textless \   16^{2} ;
Finally, 0 < x < 256;
The correct answer is A.
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