All categories

2 years ago

5 2/3 + 7 5/9 ples I nnmed help

Mathematics

1 answer:

Fantom [35]2 years ago

7 0

Answer:

Step-by-step explanation:

Solution

=5 2/3 + 7 5/9

=3×5+2/3+9×7+5/9

=17/3+68/9

=119/9

=13.22

Hope it helped you.

You might be interested in

Please help will mark brainliest

Lynna [10]

Z^5/8

You can tell this because exponents get added together when multiplying and the fact that the fraction goes down by a multiple of 1/8.

6 0

3 years ago

Abcducbsdjkcndsjkcbdjkcnusjckhnqsulcjhnslich.snuc.jsncus.jbcnsu.cjkbsscbsjcnjscnsa

Illusion [34]

did this answer your question...no. OK well that is your loss

4 0

3 years ago

2+3x34 what is the answer in unit form

S_A_V [24]

Answer:

3 x 34 = 102 + 2 = 104 is your answer just do the equation

8 0

3 years ago

Someone please explain how this make sense

Andru [333]

Answer:

6x + 12y = 816

Step-by-step explanation:

6 dollars per regular admission

12 dollars per both dance and volleyball

in total 816 dollars

3 0

2 years ago

Find all roots: x^3 + 7x^2 + 12x = 0 Show all work and check your answer.

Aliun [14]

The three roots of x^3 + 7x^2 + 12x = 0 is 0,-3 and -4

Solution:

We have been given a cubic polynomial.

$x^{3}+7 x^{2}+12 x=0$

We need to find the three roots of the given polynomial.

Since it is a cubic polynomial, we can start by taking ‘x’ common from the equation.

This gives us:

$x^{3}+7 x^{2}+12 x=0$

$x\left(x^{2}+7 x+12\right)=0$ ----- eqn 1

So, from the above eq1 we can find the first root of the polynomial, which will be:

x = 0

Now, we need to find the remaining two roots which are taken from the remaining part of the equation which is:

$x^{2}+7 x+12=0$

we have to use the quadratic equation to solve this polynomial. The quadratic formula is:

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Now, a = 1, b = 7 and c = 12

By substituting the values of a,b and c in the quadratic equation we get;

$\begin{array}{l}{x=\frac{-7 \pm \sqrt{7^{2}-4 \times 1 \times 12}}{2 \times 1}} \\\\{x=\frac{-7 \pm \sqrt{1}}{2}}\end{array}$

Therefore, the two roots are:

$\begin{array}{l}{x=\frac{-7+\sqrt{1}}{2}=\frac{-7+1}{2}=\frac{-6}{2}} \\\\ {x=-3}\end{array}$

And,

$\begin{array}{c}{x=\frac{-7-\sqrt{1}}{2}} \\\\ {x=-4}\end{array}$

Hence, the three roots of the given cubic polynomial is 0, -3 and -4

4 0

3 years ago