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3 years ago

6

jada applies two transformations to a polygon in the coordinate plane One of the translations is a translation and the pother is

a reflection what information does jada need to provide to communicate the transformation she has used?

1 answer:

anygoal [31]3 years ago

4 0

Answer:

What other information does Jada need to communicate about this sequence of transformations

Step-by-step explanation:

You might be interested in

Compute the average (mean) from the data shown. (round to the nearest tenth)

Alexus [3.1K]

Answer:

(C) 75.1

Step-by-step explanation:

Add all the numbers then divide by numbers of numbers their are

91+91+91+97+65+37+41+76+ 87= 676

676/9= 75.1111111111 and it goes on forever

6 0

3 years ago

Read 2 more answers

Consider the inverse function. Which conclusions can be drawn about f(x) = x2 + 2? Select three options. f(x) has a limited rang

PolarNik [594]

Answer:

f(x) has a limited range

f(x) has a maximum at the point (0, 2)

f(x) has a y-intercept at the point (0, 2).

Step-by-step explanation:

Given the function;

f(x) = x^2+2

The domain is the value of the input variables for which the function will exist. According to the expression given, the function exists on all real values of x. The same goes with range which deals with the output values. It also exists on all real values from 2 and above.

Hence f(x) have a limited range (since values less than 2 are not included compare to domain that exists on all real values) and does not have a restricted domain.

For the x intercept, x intercept occur at y = 0

substitute y = 0 into the function and get y

if y = f(x)

y = x^2+2

0 = x^2 + 2

x^2 = -2

x = 2i

Hence f(x) does not have an x-intercept of (2, 0)

For the y intercept, y intercept occur at x = 0

substitute x = 0 into the function and get y

if y = f(x)

y = x^2+2

y = 0^2 + 2

y = 2

Hence f(x) has a y-intercept at point (0, 2)

f(x) is at maximum if d(fx))/dx = 0

d(fx))/dx = 2x

since d(fx))/dx = 0

0 = 2x

x = 0

substitute x = 0 into the function

f(x) = x^2 + 2

y = 0^2+2

y = 2

Hence f(x) has a maximum at the point (0, 2)

5 0

2 years ago

Read 2 more answers

Is 81 a multiple of 3? Explain, Is 46 a multiple of 4, Explain, Is 55 a multiple of 7? Explain Is 72 a multiple of 9 explain, Is

ra1l [238]

3x27=81 so 81 is a multiple of 3

there is no integer x for which 4x=46 so 46 is not a multiple of 4

there is no integer x for which 7x=55 so 55 is not a multiple of 7

72 = 8*9 so 72 is a multiple of 9

there is no integer x for which 6x=45 hence 45 is not a multiple of 6

6 0

3 years ago

Given ∆QRS≅∆TUV, QS=5v+3, and TV=6v−9, find the length of QS and TV.?

Kisachek [45]

If <span>∆QRS≅∆TUV, Their corresponding sides would be equal so,
QS = TV
5v + 3 = 6v - 9
6v - 5v = 3 + 9
v = 12

Now, QS = TV = 5(12) + 3 = 60 + 3 = 63

In short, Your Answer would be Option B

Hope this helps!</span>

7 0

3 years ago

Which expression should you simplify to find the 90% confidence interval,

Alex787 [66]

Answer:

$0.45 - 1.96\sqrt{\frac{0.45(1-0.45)}{36}}=0.287$

$0.45 + 1.96\sqrt{\frac{0.45(1-0.45)}{36}}=0.613$

And we can conclude at 95% of confidence that the true proportion of interest for this case is between 0.287 and 0.613

Step-by-step explanation:

The estimated proportion of interest is $\hat p=0.45$

We need to find a critical value for the confidence interval using the normla standard distributon. For this case we have 95% of confidence, then the significance level would be given by $\alpha=1-0.95=0.05$ and $\alpha/2 =0.025$ . And the critical value is:

$z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96$

The confidence interval for the true population proportion is interest is given by this formula:

$\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$

Replacing the values provided we got:

$0.45 - 1.96\sqrt{\frac{0.45(1-0.45)}{36}}=0.287$

$0.45 + 1.96\sqrt{\frac{0.45(1-0.45)}{36}}=0.613$

And we can conclude at 95% of confidence that the true proportion of interest for this case is between 0.287 and 0.613

8 0

3 years ago