Question

Plot the points on a graph.A(0,0);B(0,2);C(2,2);D(2,0). Join AB, BC,CD and AD. What is the figure formed? Find the area of the figure. ​

Answer 1

$\large \green{ \underline{ \blue{ \boxed{\bf{ \red{Given -}}}}}}$

Four points which lie at (0,0) ; (0,2) ; (2,2) ; (2,0)

$\large \green{ \underline{ \blue{ \boxed{\bf{ \red{To \: Find-}}}}}}$

What is the figure formed?What is the area of the figure?

$\large \green{ \underline{ \blue{ \boxed{\bf{ \red{Solution-}}}}}}$

The given points lie on graph as per the order given in the attachment.

Which shape?

As the points lie 2 units apart from their adjacent sides. It can be a square or rhombus.

The opposite pairs of sides are also parallel to each other. The adjacent sides of the figure formed are also perpendicular to each other.

Hence! the figure formed is a square.

What is the area?

$\large{\sf{ \longmapsto Area_{(square)} = s \times s}}$

$\large{\sf{ \longmapsto Area_{(square)} = {s}^{2} }}$

$\large{\sf{ \longmapsto Area_{(square)} = {(2)}^{2} }}$

$\large{\sf{ \longmapsto Area_{(square)} = 4 \: sq. \: units}}$