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Bumek [7]
3 years ago
8

Find the value of p for which the given pair of linear equations have infinitely many solutions for 4X + 3 Y - 4 is equals to ze

ro 3 X + 9 Y + 12 is equal to zero
plz answer fast​
Mathematics
1 answer:
tino4ka555 [31]3 years ago
4 0

Answer:

x=8/3

y= -20/9

Step-by-step explanation:

4X + 3Y -4 =0

Linear egquations must in

x + y = 0

so 4X + 3Y =4

THEN

3X + 9Y = - 12

next use calculator to solve it or you can use traditional way

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Simplify 3^8 x 3^4 / 3^2 x 3^8 leaving your answer in index form
Furkat [3]

Answer:

3² or 9

Step-by-step explanation:

Step 1: Add exponents

\frac{3^{12}}{3^{10}}

Step 2: Subtract exponents

You should get 3² because of exponent rules. Remember when you multiply exponents you add the powers and when you divide exponents you subtract the powers.

3 0
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The student council is selling cupcakes at the school play.
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Answer: 37.5

Step-by-step explanation:

75 divided by 2

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The residual plot for a data set is shown.
Cerrena [4.2K]

Answer:

The regression line is not a good model because there is a pattern in the residual plot.

Step-by-step explanation:

Given is a  residual plot for a data set

The residual plot shows scatter plot of x and y

The plotting of points show that there is not likely to be a linear trend of relation between the two variables. It is more likely to be parabolic or exponential.

Hence the regression line cannot be a good model as they do not approach 0.

Also there is not a pattern of linear trend.

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3 years ago
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Simplify the following​
den301095 [7]

Answer:

1) 11\sqrt{3}

2) 2\sqrt{2}

3) 20\sqrt{3}  + 15\sqrt{2}

4) 53 + 12\sqrt{10}

5) -2

6) 7\sqrt{2}  - 5\sqrt{3}

Step-by-step explanation:

1) 2\sqrt{12} + 3\sqrt{48} - \sqrt{75}

=(2 × 2\sqrt{3} )+ (3 × 4\sqrt{3}) - 5\sqrt{3}

= 4\sqrt{3} + 12\sqrt{3} - 5\sqrt{3}

= 11\sqrt{3}

2) 4\sqrt{8} -2\sqrt{98} + \sqrt{128}

= (4 × 2\sqrt{2}) - (2 × 7\sqrt{2}) + 8\sqrt{2}

= 8\sqrt{2} - 14\sqrt{2} +8\sqrt{2}

= 2\sqrt{2}

3) 5\sqrt{12\\} - 3\sqrt{18} + 4 \sqrt{72}  +2\sqrt{75}

= 5× 2\sqrt{3} - 3×3\sqrt{2} + 4×6\sqrt{2} + 2×5\sqrt{3}

= 10\sqrt{3} - 9\sqrt{2} +24\sqrt{2} +10\sqrt{3}

= 20\sqrt{3}  + 15\sqrt{2}

4) (2\sqrt{2}  + 3\sqrt{5} )^{2}

= 8 + 12\sqrt{10} + 45

= 53 + 12\sqrt{10}

5) (1+\sqrt{3} ) (1-\sqrt{3} )

= 1 - 3

= -2

6) (2\sqrt{6} -1) (\sqrt{3} -\sqrt{2}  )

= 2\sqrt{18}-2\sqrt{12}  -\sqrt{3}  +\sqrt{2}

= 2×3\sqrt{2} - 2×2\sqrt{3} - \sqrt{3} + \sqrt{2}

= 6\sqrt{2}  - 4\sqrt{3} -\sqrt{3} +\sqrt{2}

= 7\sqrt{2}  - 5\sqrt{3}

Hope the working out is clear and will help you. :)

5 0
3 years ago
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What is the area and perimeter?
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Answer:

Step-by-step explanation:

Area is 10x10=100+6x5=130

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4 years ago
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