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3 years ago

Solve the inequality graphically.

Mathematics

1 answer:

Ratling [72]3 years ago

8 0

Answer:

D, X<0

‎‎‎‎‎‎‎‎ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

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Is 1/3 a irrational number?

LenKa [72]

Answer: 13 is a rational number

Step-by-step explanation: By definition, a rational number is a number q that can be written as a fraction in the form q=a/b where a and b are integers and b≠0. So, 1/3 is rational because it is exactly what you get when you divide one integer by another.

8 0

3 years ago

The base of a 15-foot ladder is 6 feet from a building. If the ladder reaches the flat roof, how tall is the building?

Vlad [161]

Answer:

the answer would be 13.75 feet

Step-by-step explanation:

The computation of the tall is the building as follows:

Given that

Base is 6 foot

And, the hypotheses is 15 feet

Here we use the Pythagoras theorem

= √15^2 - √6^2

= √225 - √36

= √189

= 13.75 feet

Hence the answer would be 13.75 feet

6 0

3 years ago

Karens batting average is 0.444.she was at bat 45 times. how many hits did she get

alexgriva [62]

Answer:

A batting average is simply the ratio of hits/at-bats. So, if Karen were up to bat 1,000 times and she got a hit 444 times, that makes her batting average 444/1,000 = .444.

The good news is you can multiply this ratio by number of at bats to get the number of hits.

So, 45 hits x .444 = your answer.

Hope that helps.

4 0

3 years ago

Determine the 5th term in geometric sequence whose first term is 4 and whose common ratio is 3

amid [387]

Formula for geometric sequence is aₓ = arⁿ⁻1
a₅=4(3)⁵⁻¹
a₅=4(3)⁴
a₅=4(81)
a₅=324

8 0

3 years ago

An automobile dealer had 288 cars and trucks in stock during the month. He must pay an inventory fee of 52 per car and $5 per tr

Aleonysh [2.5K]

For the given conditions, we won’t get a practical solution.

<u>Solution:</u>

Given, An automobile dealer had 288 cars and trucks in stock during the month.

He must pay an inventory fee of 52 per car and $5 per truck.

He paid $849 for inventory foes.

We have to find how many cars and Trucks did he have during the month?

Now, let the number of trucks be n, then number of cars will be 288 – n

And, according to given information,

$\begin{array}{l}{5 \times n+52 \times(288-n)=849} \\\\ {\rightarrow 5 n+52 \times 288-52 n=849} \\\\ {\rightarrow 52 n-5 n=14976-849} \\\\ {\rightarrow 47 n=14127} \\\\ {\rightarrow n=300.57}\end{array}$

Here we got n > number of cars and trucks, which is practically impossible.

Hence, for the given conditions, we won’t get a practical solution

8 0

3 years ago