Answer:
657kg
Step-by-step explanation:
405 ÷ 45 = 9
9 x 73 = 657kg
I hope this helps!
Answer:
from April to May is 17%
from May to June is 29%
Step-by-step explanation:
24.
April 30 hr * 6.5 = 195
May 35 * 6.50 = 227.50
percent increase = (new-original)/original
(227.5 - 195)/195
= 32.50/195
.166666
to change from decimal to percent , multiply by 100
= 16.67%
round to the nearest whole percent
=17%
b) May 35 * 6.50 = 227.50
June 45* 6.50 = 292.50
percent increase = (new-original)/original
= (292.50-227.50)/227.50
= 65/227.50
=.285714
to change from decimal to percent , multiply by 100
28.57 %
round to the nearest whole percent
29%
The Sine or Sinθ in a right-angle triangle is the ratio of its perpendicular to its Hypotenuse. The length of the wire is 81.5 meters.
<h3>What is Sine (Sinθ)?</h3>
The Sine or Sinθ in a right-angle triangle is the ratio of its perpendicular to its Hypotenuse. it is given as,
Sin(θ) = Perpendicular/Hypotenuse
where,
θ is the angle,
Perpendicular is the side of the triangle opposite to the angle θ,
The hypotenuse is the longest side of the triangle.
The length of the tower is 80 meters, while the angle of elevation is 79°. Therefore, the length of the wire will be the hypotenuse of the triangle. Therefore, the length of the wire is,
Sin(θ) = Perpendicular/Hypotenuse
Sin(79°) = 80 meter/Length of the wire
Length of the wire = 81.4973 ≈ 81.5 meters
Hence, the length of the wire is 81.5 meters.
Learn more about Sine:
brainly.com/question/21286835
#SPJ1
Answer:
P(A) = 0.2
P(B) = 0.25
P(A&B) = 0.05
P(A|B) = 0.2
P(A|B) = P(A) = 0.2
Step-by-step explanation:
P(A) is the probability that the selected student plays soccer.
Then:
P(B) is the probability that the selected student plays basketball.
Then:
P(A and B) is the probability that the selected student plays soccer and basketball:
P(A|B) is the probability that the student plays soccer given that he plays basketball. In this case, as it is given that he plays basketball only 10 out of 50 plays soccer:
P(A | B) is equal to P(A), because the proportion of students that play soccer is equal between the total group of students and within the group that plays basketball. We could assume that the probability of a student playing soccer is independent of the event that he plays basketball.
Is this all one problem?
If not here:
56+64=120
30+54= 84
55+66= 121
40+25= 65
48+14= 64
24+40= 64
49+63= 112
62+15= 77
And the GCF of all of these is 1.
