Step-by-step explanation:
first in time : original. 2a : of, relating to, or being a prime number — compare relatively prime. b : having no polynomial factors other than itself and no monomial factors other than 1 a prime polynomial.
Answer is c.
t = 0.5(d+h)
multiply both sides by 2 to cancel out the 0.5.
2t = d+h
2t - d = h
D) attached is a picture, I would’ve typed it out but I can’t use the square root symbol
Answer:
There are 165 ways to distribute the blackboards between the schools. If at least 1 blackboard goes to each school, then we only have 35 ways.
Step-by-step explanation:
Essentially, this is a problem of balls and sticks. The 8 identical blackboards can be represented as 8 balls, and you assign them to each school by using 3 sticks. Basically each school receives an amount of blackboards equivalent to the amount of balls between 2 sticks: The first school gets all the balls before the first stick, the second school gets all the balls between stick 1 and stick 2, the third school gets the balls between sticks 2 and 3 and the last school gets all remaining balls.
The problem reduces to take 11 consecutive spots which we will use to localize the balls and the sticks and select 3 places to put the sticks. The amount of ways to do this is
As a result, we have 165 ways to distribute the blackboards.
If each school needs at least 1 blackboard you can give 1 blackbooard to each of them first and distribute the remaining 4 the same way we did before. This time there will be 4 balls and 3 sticks, so we have to put 3 sticks in 7 spaces (if a school takes what it is between 2 sticks that doesnt have balls between, then that school only gets the first blackboard we assigned to it previously). The amount of ways to localize the sticks is
. Thus, there are only 35 ways to distribute the blackboards in this case.
3/4x - 16 = 28
+16 +16
3/4x = 44
*3/4 *3/4
x = 176/3