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3 years ago

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-17 -5(X+3) = 3x solve

1 answer:

Gelneren [198K]3 years ago

3 0

-17 -5 (x + 3) = 3x Use the Distributive Property
-17 -5x - 15 = 3x Combine like terms (-17 and -15)
-32 - 5x = 3x Add 32 to both sides
-5x = 3x + 32 Subtract 3x from both sides
-8x = 32 Divide both sides by -8
x = -4

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Which would be used to solve this equation? Check all that apply.

puteri [66]

Answer:

multiplying both-side of the equation by 3

substituting 36 for p to check the solution

Step-by-step explanation:

To solve the equation p/3 = 12, we will follow the steps below;

first multiply 3 to both-side of the equation, that is:

p/3 × 3 = 12 × 3

On the left-hand side of the equation, 3 at the numerator will cancel-out 3 at the denominator, leaving us with just p while on the right-hand side of the equation 12 will be multiplied by 3

p= 36

To check the correctness of the equation, we can substitute p = 36 back into the equation and then check, that is;

p/3 = 12

36/3 = 12

This implies p = 36 is correct

3 0

3 years ago

Janey drove 355 km, and the trip took 5 hrs. at what average was janey traveling?<br>use d=rt

stiks02 [169]

71 is the correct answer.

355 divided by 5 = 71

4 0

3 years ago

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d1i1m1o1n [39]

Step-by-step explanation:

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5 0

3 years ago

A Simple random sample of 100 8th graders at a large suburban middle school indicated that 84% of them are involved with some ty

Setler [38]

Answer: a) (0.755, 0.925)

Step-by-step explanation:

Let p be the population proportion of 8th graders are involved with some type of after school activity.

As per given , we have

n= 100

sample proportion: $\hat{p}=0.84$

Significance level : $\alpha= 1-0.98=0.02$

Critical z-value : $z_{\alpha/2}=2.33$ (using z-value table)

Then, the 98% confidence interval that estimates the proportion of them that are involved in an after school activity will be :-

$\hat{p}\pm z_{\alpha/2}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}$

i.e. $0.84\pm (2.33)\sqrt{\dfrac{0.84(1-0.84)}{100}}$

i.e. $\approx0.84\pm 0.085$

i.e. $(0.84- 0.085,\ 0.84+ 0.085)=(0.755,\ 0.925)$

Hence, the 98% confidence interval that estimates the proportion of them that are involved in an after school activity : a) (0.755, 0.925)

3 0

3 years ago

4) Arnold ate breakfast at a restaurant. His total came to $76.75. There is an 8% sales tax and 15% tip. What is Arnold's total

lisov135 [29]

Answer:

The total cost is $95.32.

Step-by-step explanation:

Given:

Total came to $76.75. There is an 8% sales tax and 15% tip.

Now, to find the total cost.

<em>8% sales tax is there so we calculate the amount after adding sales tax:</em>

$76.75 + 8% of $76.75

$76.75+\frac{8}{100}\times 76.75$

$76.75+0.08\times 76.75$

$76.75+6.14$

$82.89$

The cost after sales tax is $82.89.

Now, <em>the cost after 15% tip:</em>

$82.89 + 15% of $82.89

$82.89+\frac{15}{100}\times 82.89$

$82.89+0.15\times 82.89$

$82.89+12.43$

$95.32$

The cost after the tip is $95.32.

Therefore, the total cost is $95.32.

8 0

3 years ago