If it takes 20 minute to get to the airport, and he wants to be there an hour and 5 minutes before his flight leaves, we have to subtract the time he leaves (9:50) by 1 hour and 5.
9:50 - 1 hour and 5 minutes.
9:50 - 65 minutes.
9:50 - 65 = 8:45.
Which means he must be at the airport at 8:45.
BUT,
The question is asking for the latest time that Quincy can LEAVE for the airport, which means it's 8:45 - 20 minutes, since it takes 20 minutes to get to the airport:
8:45 - 20 = 8:25
Answer:
Graph # 3
Step-by-step explanation:
-2x + 5y > 15 Let x = 0 solve for y
-2(0) + 5y = 15 change the > to an =
5y = 15
y =3 Point (0, 5) is on the graph
Graph # 3 is correct because the y-intercept is 5
x y
0 3 -2(0) + 5y = 15; 5y = 15
5 5 -2(5) + 5y = 15; -10 + 5y = 15; 5y = 25; y = 5
10 7 -2(10) + 5y = 15; -20 + 5y = 15; 5y = 35; y = 7
The graph > the line is dotted and you will shade above the line
Assume x are Erica's classes & y are Bo's classes.
x+y=35
x=2y-13
Replacing the value of x into the first equation
2y-13+y=35
3y=35+13
y=16 classes
x=2*16-13=19 classes
Rewrite the equation:
-2x^2 - 3x + 8 = 0
2x^2 + 3x -8 =0
Where a=2, b=3 and c=-8
Then b^2 - 4ac = 3^2 - 4(2)(-8) = 9 + 64 = 73
A positive discriminant implies that the equation has two different real solutions.
Answer: the discriminant is 73, so the equation has 2 real solution
