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Roman55 [17]
4 years ago
7

1. Five more than twice a number is 7.

Mathematics
2 answers:
Nataly [62]4 years ago
8 0

Answer:

5+2n=7

Step-by-step explanation:

5+2n=7

7-5=2n

2=2n

2÷2=1

n=1

VashaNatasha [74]4 years ago
3 0
Let’s say the number is “n”

First it’s telling u twice a number meaning the number is going to multiply by 2 so

2 X n (X means multiplication) or 2n

Then it states five more than which means to add 5 to what follows so

2n + 5

It’s saying it’s 7 so

2n+5=7
2n= 7-5
2n=2
2n/2=2/2
N=1

The final answer is 1 meaning the number is 1
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If the integers have different absolute values ... they're different numbers with different
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Examples:

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Cos (90-theta) • cosec90-theta) =tano. How?​
denis-greek [22]

Answer:

<u>______________________________________________________</u>

<u>TRIGONOMETRY IDENTITIES TO BE USED IN THE QUESTION :-</u>

For any right angled triangle with one angle α ,

  • \cos (90 - \alpha  ) = \sin \alpha  or  \sin(90 - \alpha ) = \cos\alpha
  • cosec \: (90 - \alpha  ) = \sec\alpha   or  \sec(90 - \alpha ) = cosec\:\alpha

<u>SOME GENERAL TRIGNOMETRIC FORMULAS :-</u>

  • <u></u>\sin \alpha = \frac{1}{cosec \: \alpha }  or  cosec \: \alpha  = \frac{1}{\sin \alpha }
  • <u></u>\cos \alpha = \frac{1}{\sec \alpha }  or  \sec \alpha = \frac{1}{\cos \alpha }

<u>______________________________________________________</u>

Now , lets come to the question.

In a right angled triangle , let one angle be α (in place of theta) .

So , lets solve L.H.S.

\cos (90 - \alpha ) \times cosec(90 - \alpha )

=> sin\alpha  \times \sec\alpha

=> \sin\alpha  \times \frac{1}{\cos\alpha }

=> \frac{\sin\alpha }{\cos\alpha }

=> \tan\alpha = R.H.S.

∴ L.H.S. = R.H.S. (Proved)

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Answer:

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Step-by-step explanation:

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