Answer:
<em>90 calories in total</em>
Step-by-step explanation:
<em>We can solve this equation through the following steps:</em>
<em>Step One: Since we are told that a banana is 20 less calories than an orange, we can create the Let Statements:</em>
<em>Let x= the calories in a banana</em>
<em>Let x-20=the calories in an orange</em>
<em>Step Two: Create an equation</em>
<em>Since we are told "7 bananas have the same calories as 9 oranges" we translate"</em>
<em>7x=9(x-20) Distribute</em>
<em>7x=9x-180 Subtract 9x from both sides of the equation</em>
<em>7x-9x=-180 Simplify</em>
<em>-2x=180 Divide both sides by -2</em>
<em>x=90</em>
<em>∴There are 90 calories in a banana. </em>
Answer:
I'm pretty sure that all of the Prime numbers only have two factors. Let's say 3 for an example.
Step-by-step explanation:
The number 3 only has the factors of 3 and 1.
The two factors are itself (of course) and 1 (any number can go into one).
Another way to do this if you had to find out an answer like this.
3x1=3. Any number that can go into itself times 1 has only 2 factors.
Or at least I think. This is probably wrong. So Sorry if it is.
Answer:
he added the dimensions of the rectangle. He used the wrong formula. the formula he used was length + breadth. He should have multiplied by 2
6x + 8y +8
Step-by-step explanation:
Perimeter of a rectangle = 2 x (L + B)
L = length
b = breadth
2 (3x + 4y + 4. ) = 6x + 8y +8
Answer:
MAG ARAR KA BōBõ
Step-by-step explanation:
MAG ARAR KA BōBõ
Answer:
A task time of 177.125s qualify individuals for such training.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean 
and standard deviation 
, the zscore of a measure X is given by
After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. Subtracting 1 by the pvalue, we This p-value is the probability that the value of the measure is greater than X.
In this problem, we have that:
A distribution that can be approximated by a normal distribution with a mean value of 145 sec and a standard deviation of 25 sec, so 
.
The fastest 10% are to be given advanced training. What task times qualify individuals for such training?
This is the value of X when Z has a pvalue of 0.90.
Z has a pvalue of 0.90 when it is between 1.28 and 1.29. So we want to find X when 
.
So
A task time of 177.125s qualify individuals for such training.
