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FrozenT [24]
4 years ago
10

Giving two reasons,classify air as a mixture or compound.

Chemistry
1 answer:
ollegr [7]4 years ago
4 0
1.) Air can be separated into its constituents such as oxygen, nitrogen etc.

2.) Air has a variable composition because at different places different amount of gases are present in air.
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Draw the other possible resonance structure of each organic ion. In each case, draw the structure that minimizes formal charges.
pshichka [43]

Three resonance structures  can be drawn for the allyl cation while two resonance structures can be drawn for the amidate ion.

Sometimes, we cannot fully describe the bonding in a chemical specie using a single chemical structure. In such cases, we have to use a number of structures which cooperatively represent the actual bonding in the molecule. These structures are called resonance or canonical structures.

The resonance structures of the allyl cation and the amidate ion are shown in the images attached to this answer. These structures show the different bonding extremes in these organic ions.

Learn more: brainly.com/question/4933048

7 0
3 years ago
A newspaper headline says that the average home uses about 30 kilowatt-hours per day. What is a kilowatt?
ch4aika [34]
A Kilowatt is bigger than a Watt. A measure of 1,000 Watts of power.


6 0
3 years ago
Read 2 more answers
The distance traveled divided by the time taken to travel the distance is _
BigorU [14]
Speed is the distance traveled divided by the time. This can also be written as Speed =  \frac{Distance}{Time}. Hope this helped!
3 0
4 years ago
A 20 g granite boulder absorbs 300.2 Joules of energy from the Sun, resulting in its temperature
s344n2d4d5 [400]

Answer:

19 °C

Explanation:

Step 1: Given and required data

  • Mass of granite (m): 20 g
  • Heat absorbed (Q): 300. 2 J
  • Specific heat capacity of granite (c): 0.790 J/g.°C

Step 2: Calculate the temperature change (ΔT)

We will use the following expression.

Q = c × m × ΔT

ΔT = Q/c × m

ΔT = 300.2 J/(0.790 J/g.°C) × 20 g = 19 °C

3 0
3 years ago
What is the sound intensity level in decibels of ultrasound of intensity 7.53 ✕ 104 W/m2, used to pulverize tissue during surger
Ghella [55]

Answer : The intensity of sound level in decibels is, 169 dB

Explanation:

The expression used for the intensity of sound level is given by the equation:

P=10\times \log \frac{I}{I_o}

where,

I = final intensity = 7.53\times 10^4W/m^2

I_o = initial intensity = threshold intensity of human hearing = 10^{-12}W/m^2

Now put all the given values in the above formula, we get:

P=10\times \log \frac{7.53\times 10^4W/m^2}{10^{-12}W/m^2}

P=168.767dB\approx 169dB

Thus, the intensity of sound level in decibels is, 169 dB

4 0
4 years ago
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