Question

A solid sphere of mass 0.6040 kg rolls without slipping along a horizontal surface with a translational speed of 5.080 m/s. It comes to an incline that makes an angle of 33.00° with the horizontal surface. To what vertical height above the horizontal surface does the sphere rise on the incline?

Answer 1

Answer:

1.315 m

Explanation:

Assumption: there is no resistance of any type

v= 5.08 m/s

g = 9.81m/s^2

change in kinetic energy = change in gravitational potential energy

$\frac{mv^{2} }{2} = mgh$

mass on both side is same so it cancels out

and also making 'h' alone on one side

$h = \frac{v^{2} }{2g}$    

h= ((5.08)^2)/(2*9.81)

 h =1.3153m