Answer:
63.78%
Explanation:
The equation that relates the angle of the polarization and the intensity of ligth transmitted is I=Io*cos²(x), where I is the intensity of the incident light, Io is the intensity of the transmitted light, and x is the angle of polarization. The fraction of incident light will be I/Io, so the answer in given by cos²(37) = 0.6378
The sleds speed when the spring returns toits uncompressed length is v = 0.03 m/s.
<u>Explanation</u>:
Given,
force constant = 42 N/cm = 0.42 N/m, mass m = 68 kg, spring x = 0.39 m
The potential energy, U, stored in the spring is
U = 1/2 kx^2
= 1 / 2
0.42
(0.39)^2
= 0.032 J
All its potential energy has been converted into kinetic energy since it has a uncompressed length.
K = 1/2 mv^2
v = sqrt (2K / m)
= √(( 2
0.032) / 68)
v = 0.03 m/s
.
Answer:
0.2932 rad/s
Explanation:
r = Radius = 2 m
= Initial angular momentum = 
= Initial angular velocity = 14 rev/min
= Final angular momentum
= Final angular velocity
Here the angular momentum of the system is conserved

The final angular velocity is 0.2932 rad/s