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CaHeK987 [17]
2 years ago
15

Benford’s law states that the probability that a number in a set has a given leading digit, d, is

Mathematics
2 answers:
Scilla [17]2 years ago
4 0
<span>Benford’s law states that the probability that a number in a set has a given leading digit, d, is
P(d) = log(d + 1) - log(d)</span>  
The division property of logarithm should be use to make it as a single logarithm  
P(d) = log ( (d + 1)/ d)  
So the probability that the number 1 is the leading digit is
P(1) = log ( ( 1+1)/ 1)
P(1) = log ( 2)
<span>P(1) = 0.301</span>
Mashutka [201]2 years ago
4 0

The exact right answer fore this question would be...


Use the quotient property to rewrite the expression.

Write the difference of logs as the quotient log((d+1)/d).

Substitute 1 for d to get log(2).

Since log(2) = 0.30, the probability that the number 1 is the leading digit is about 30%.

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Answer:

1. 32 ounces

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Step-by-step explanation:

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3 years ago
PLSSS HELP ASAP<br> solve questions 1-5 please
sertanlavr [38]

#1. 4x^2 + 17 - 15 = 0

Use the roots given, and plug them in to a factored form. Then, foil! It can also be helpful to multiply the equation to get rid of decimals/fractions.

(x - 3/4)(x + 5) = 0

x^2 - 3/4x + 5x - 3 3/4 = 0

x^2 + 4.25 - 3.75 = 0 (multiply everything by 4)

4x^2 + 17 - 15 = 0

#2. y = 0, -4

Both 4y^2 and 16y contain a 4 in the coefficient and a y in the variables. Therefore, we can factor out a 4y from each.

4y(y + 4) = 0

Then, set both parts of the factored equation equal to 0.

4y = 0

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y + 4 = 0

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#3. a = 0, -3

Both 6a^5 and 18a^4 contain a 6 in the coefficient and an a in the variables. Therefore, we can factor out a 6a^4 from each.

6a^4(a + 3) = 0

Then, set both parts of the factored equation equal to 0.

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#4. x = -8

We are looking for two terms that multiply to equal a * c, and add up to equal b. We know that 8 + 8 = 16, and 8 * 8 = 64. There are no negatives in this equation, therefore both signs in our factored form are positive.

(x + 8)(x + 8) = 0

x + 8 = 0

x = -8

#5. x = -8, 8

First, subtract 64 from both sides. The key word here is 'factoring.' If this was not present, there is a different way (which may be easier for some).

x^2 = 64

x^2 - 64 = 0

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(x - 8)(x + 8) = 0

x - 8 = 0

x = 8

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Hope this helps!! :)

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Step-by-step explanation:

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