Benford’s law states that the probability that a number in a set has a given leading digit, d, is

2 answers:

4 0

<span>Benford’s law states that the probability that a number in a set has a given leading digit, d, is
P(d) = log(d + 1) - log(d)</span>
The division property of logarithm should be use to make it as a single logarithm
P(d) = log ( (d + 1)/ d)
So the probability that the number 1 is the leading digit is
P(1) = log ( ( 1+1)/ 1)
P(1) = log ( 2)
<span>P(1) = 0.301</span>

Mashutka [201]3 years ago

4 0

The exact right answer fore this question would be...

Use the quotient property to rewrite the expression.

Write the difference of logs as the quotient log((d+1)/d).

Substitute 1 for d to get log(2).

Since log(2) = 0.30, the probability that the number 1 is the leading digit is about 30%.

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