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CaHeK987 [17]
3 years ago
15

Benford’s law states that the probability that a number in a set has a given leading digit, d, is

Mathematics
2 answers:
Scilla [17]3 years ago
4 0
<span>Benford’s law states that the probability that a number in a set has a given leading digit, d, is
P(d) = log(d + 1) - log(d)</span>  
The division property of logarithm should be use to make it as a single logarithm  
P(d) = log ( (d + 1)/ d)  
So the probability that the number 1 is the leading digit is
P(1) = log ( ( 1+1)/ 1)
P(1) = log ( 2)
<span>P(1) = 0.301</span>
Mashutka [201]3 years ago
4 0

The exact right answer fore this question would be...


Use the quotient property to rewrite the expression.

Write the difference of logs as the quotient log((d+1)/d).

Substitute 1 for d to get log(2).

Since log(2) = 0.30, the probability that the number 1 is the leading digit is about 30%.

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Write y-5=6(x+1) in standard form and show work plz. Thanks
Nezavi [6.7K]

Answer:

x = (1/6y)+(-11/6)

Step-by-step explanation:

Step 1: Flip the equation.

6x+6=y−5

Step 2: Add -6 to both sides.

6x+6+−6=y−5+−6

6x=y−11

Step 3: Divide both sides by 6.

6x /6 = y−11 /6

x= (1 /6 y)+ (−11 /6)

Answer:

x = (1/6y)+(-11/6)

5 0
4 years ago
It is also called as the constant of proportionality. It is also called as the constant of proportionality. *
snow_lady [41]

Answer:

constant of variation

Step-by-step explanation:

Constant of variation and constant of proportionality mean the same and they are used in variations.

For instance:

y = 2x

In the above equation, y varies directly as x and the constant of proportionality or variation is 2.

<em>It is often represented with k (though, other alphabets can also be used)</em>

8 0
3 years ago
Please help me thank you
Mashcka [7]

Answer:

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Step-by-step explanation:

it's really easy when they ask you this just put the number in parentheses instead of the x because x is an unknown number it's telling you to multiply the 6 by the number they give you

6 0
3 years ago
How do you the distributive property to write an equivalent expression for 2(9+5k).
Nonamiya [84]
2(9) + 2(5k)
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6 0
4 years ago
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