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2 years ago

Write your answer simplified, please.

Mathematics

2 answers:

Ede4ka [16]2 years ago

6 0

Answer:

1.6

Step-by-step explanation:

1.6

Alja [10]2 years ago

5 0

1.6 is the correct answer

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The question is the photo.

andrew-mc [135]

Answer:

w=5

Step-by-step explanation:

the triangle has the same size of area as the side of the rectangle so therefore 5

7 0

2 years ago

Read 2 more answers

Gloria is an artist. She sets a goal to paint 2 paintings every month. The number of paintings Gloria creates depends on the num

BartSMP [9]

Answer:

we get the all equation of given condition $M = 2P+1$ & $P=2M+1$ Step-by-step explanation:

Given that,

Number of painting made by Gloria every month is 2.

Gloria creates depends on the number of paintings p, Gloria paints over m months if she meet her goal.

we have to check all the apply.

According to question,

M is the independent variable and P is dependent variable.

So, Relation formed by given statement is $M =2P$

Case(1): P is increased by 2 as M is increased by 1.

Then, $M+1= 2\times (P+2)$

$M+1= 2P+2$

$M = 2P+1$

This is Equation of the given case(1).

Again, P is the independent variable and M is dependent variable.

∴ $P=2M$

Case (2) M is increased by 2 as P increased by 1.

Then, $P+1=2\times(M+2)$

$P+1=2M+2$

$P=2M+1$

Hence,

we get the all equation of given condition $M = 2P+1$ & $P=2M+1$

4 0

3 years ago

A wire b units long is cut into two pieces. One piece is bent into an equilateral triangle and the other is bent into a circle.

mezya [45]

1. Divide wire b in parts x and b-x.

2. Bend the b-x piece to form a triangle with side (b-x)/3

There are many ways to find the area of the equilateral triangle. One is by the formula A= $\frac{1}{2}sin60^{o}side*side= \frac{1}{2} \frac{ \sqrt{3} }{2} (\frac{b-x}{3}) ^{2}= \frac{ \sqrt{3} }{36}(b-x)^{2}$
A= $\frac{ \sqrt{3} }{36}(b-x)^{2}=\frac{ \sqrt{3} }{36}( b^{2}-2bx+ x^{2} )=\frac{ \sqrt{3} }{36}b^{2}-\frac{ \sqrt{3} }{18}bx+ \frac{ \sqrt{3} }{36}x^{2}$

Another way is apply the formula A=1/2*base*altitude,
where the altitude can be found by applying the pythagorean theorem on the triangle with hypothenuse (b-x)/3 and side (b-x)/6

3. Let x be the circumference of the circle.

$2 \pi r=x$

so $r= \frac{x}{2 \pi }$

Area of circle = $\pi r^{2}= \pi ( \frac{x}{2 \pi } )^{2} = \frac{ \pi }{ 4 \pi ^{2} }* x^{2} = \frac{1}{4 \pi } x^{2}$

4. Let f(x)= $\frac{ \sqrt{3} }{36}b^{2}-\frac{ \sqrt{3} }{18}bx+ \frac{ \sqrt{3} }{36}x^{2}+\frac{1}{4 \pi } x^{2}$

be the function of the sum of the areas of the triangle and circle.

5. f(x) is a minimum means f'(x)=0

f'(x)= $\frac{ -\sqrt{3} }{18}b+ \frac{ \sqrt{3} }{18}x+\frac{1}{2 \pi } x$ =0

$\frac{ -\sqrt{3} }{18}b+ \frac{ \sqrt{3} }{18}x+\frac{1}{2 \pi } x=0$

$(\frac{ \sqrt{3} }{18}+\frac{1}{2 \pi }) x=\frac{ \sqrt{3} }{18}b$

$x= \frac{\frac{ \sqrt{3} }{18}b}{(\frac{ \sqrt{3} }{18}+\frac{1}{2 \pi }) }$

6. So one part is $\frac{\frac{ \sqrt{3} }{18}b}{(\frac{ \sqrt{3} }{18}+\frac{1}{2 \pi }) }$ and the other part is b- $\frac{\frac{ \sqrt{3} }{18}b}{(\frac{ \sqrt{3} }{18}+\frac{1}{2 \pi }) }$

4 0

3 years ago

Read 2 more answers

Mary has $267 in her checking account. She writes checks for $33, $65, and $112. What is the balance in her account now?

nata0808 [166]

Answer:

267 - 112 - 65 - 33 = $57

Step-by-step explanation:

subtract to get the answer

5 0

3 years ago

What is the surface area of the rectangular prism below?

kati45 [8]

Answer:

12×6×2+6×5×2+12×5×2= 324m^2

3 0

3 years ago