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Lemur [1.5K]
3 years ago
8

Sketch a graph of -9x+6y=18

Mathematics
1 answer:
Sedaia [141]3 years ago
4 0

Here you go a graph of -9x+6y=18 hope this is correct. ;)

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5x+2y=10; (-2, 9) if -2 is x and 9 is y
Dovator [93]
What are you looking for. slope?
4 0
3 years ago
A truck weighing 150kN and travelling at 2m/sec impacts with a buffer
FrozenT [24]

The maximum compression of the spring is 0.276 m

Step-by-step explanation:

First of all, we calculate the spring  constant of the spring, by using Hooke's law:

F=kx

where

F = 10 kN = 10,000 N is the force applied

x = 1.25 cm = 0.0125 m is the corresponding compression of the spring

k is the spring constant

Solving for k,

k=\frac{F}{x}=\frac{10,000}{0.0125}=8\cdot 10^5 N/m

When the truck impacts with the spring, all the kinetic energy of the truck is converted into elastic potential energy of the spring, so we can write

\frac{1}{2}mv^2=\frac{1}{2}kx^2 (1)

where

m is the mass of the truck

v = 2 m/s is the initial speed of the truck

k=8\cdot 10^5 N/m is the spring constant

x is the compression of the spring

The mass of the truck can be found from its weight:

m=\frac{W}{g}=\frac{150,000 N}{9.81 N/kg}=15,290 kg

So now we can re-arrange eq.(1) to find the compression, x:

x=\sqrt{\frac{mv^2}{k}}=\sqrt{\frac{(15,290)(2)^2}{8\cdot 10^5}}=0.276 m

Learn more about kinetic energy:

brainly.com/question/6536722

#LearnwithBrainly

6 0
3 years ago
Assume that the radius r of a sphere is expanding at a rate of 40 cm/min. The volume of a sphere is V = 4 3 πr3 and its surface
Scrat [10]

Answer:

The rate of change in surface area when r = 20 cm is 20,106.19 cm²/min.

Step-by-step explanation:

The area of a sphere is given by the following formula:

A = 4\pi r^{2}

In which A is the area, measured in cm², and r is the radius, measured in cm.

Assume that the radius r of a sphere is expanding at a rate of 40 cm/min.

This means that \frac{dr}{dt} = 40

Determine the rate of change in surface area when r = 20 cm.

This is \frac{dA}{dt} when r = 20. So

A = 4\pi r^{2}

Applying implicit differentiation.

We have two variables, A and r, so:

\frac{dA}{dt} = 8r\pi \frac{dr}{dt}

\frac{dA}{dt} = 8*20\pi*40

\frac{dA}{dt} = 20106.19

The rate of change in surface area when r = 20 cm is 20,106.19 cm²/min.

6 0
3 years ago
What is the solution of <img src="https://tex.z-dn.net/?f=%5Cfrac%7Bx%2B2%7D%7B4%7D%20%3D%20%5Cfrac%7Bx%2B8%7D%7B3%7D" id="TexFo
Lina20 [59]

Answer:

x = -26

Step-by-step explanation:

Multiply both sides by the lowest common multiple of 4 and 3, which is 12.

3(x+2) = 4(x+8)

3x + 6 = 4x + 32 --- distribute the 4 and 3

6 = x + 32 --- subtract 3x from both sides

-26 = x --- subtract 32 from both sides

x = -26

6 0
3 years ago
A chemist has a 100 gram sample of a radioactive
Nastasia [14]

Answer:

75

Step-by-step explanation:

did it 5 mins ago

3 0
3 years ago
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