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butalik [34]
3 years ago
10

What are the domain and range of the exponential function f(x)=ab^x where b is a positive real number not equal to 1 and a>0?

Mathematics
2 answers:
dybincka [34]3 years ago
6 0

Answer:

the answer is C

Step-by-step explanation:


Studentka2010 [4]3 years ago
3 0

For this case we have a function of the form:

y = f (x)

Where f (x) = ab ^ x

The domain of that function is given by all the values that x can take.

If b is a positive real number other than 1 and a> 0, we have that the domain of f (x) is given by (-∞,∞). x can take any value.

On the other hand, the range is given by the dependent values of the variable "y".

IF we evaluate f (-∞) then y tends to zero.

If we evaluate f (∞) then y tends to infinity.

Thus, the range is: (0, ∞)

So, we have:

Domain: (-∞,∞)

Range: (0, ∞)

Answer:

Option C


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3. Which inequalities show a correct relationship between expressions?
igomit [66]

Answer: a and d

Step-by-step explanation:

First of all, we need to make a analysis of each letters:

a. factoring 32 = 2.2.2.2.2 = 2^{5}

2^{5}^{3} = 2^{15}

then,

16 = 2^{4}

but 2^{4}^{4} =2^{16}

in conclusion that, this inequality is correct

b. 27 =  3^{3}

this first situation is equal to  3^{9}

the second situation is:

81 =  3^{4}

and  3^{4}^{4} = 3^{16}

it's a mistake.

c. factoring 9: 9 = 3^{3}

3^{9} <  3^{5}

it's wrong.

d. factoring 8 = 2^{3}

factoring 32 =  2^{5}

2^{12} >  2^{10}

This is true.

Finally.. our correct answers is a and d.

3 0
3 years ago
An IPod Nano has 2 gigabytes of storage and can hold about 500 songs. The iPod Plus has 80 gigabytes of storage. How many songs
jasenka [17]
80 * 250 =20,000

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4 0
3 years ago
Read 2 more answers
The diameter of a wheel of a car is 30cm. If the car travels at an average speed of 13.2m/s, find the number of revolutions made
Marysya12 [62]

Answer:

Approximately 50420 revolutions (rounded to the nearest whole number.)

Step-by-step explanation:

Convert the diameter of this wheel to meters: d = 30\; \rm cm = 0.30\; \rm m.

Circumference of this wheel:

\pi \, d = \pi \times 0.30\; \rm m \approx 0.942\; \rm m.

Distance travelled in one hour:

\begin{aligned}v \cdot t &= 13.2 \; \rm m \cdot s^{-1} \times 3600\; \rm s \\ &= 47520\; \rm m\end{aligned}.

Number of revolutions required for covering that distance:

\displaystyle \frac{47520\; \rm m}{(\pi \times 0.30\; \rm m)} \approx 50420.

3 0
2 years ago
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6 0
2 years ago
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Alex73 [517]

Answer:

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2 years ago
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