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3 years ago

Write the equation of the line perpendicular to y=3/2x+3/2 that passes through the point (-1,2)

Mathematics

1 answer:

lbvjy [14]3 years ago

4 0

Answer:

y = -2/3x + 4/3

Step-by-step explanation:

If two lines are perpendicular, the product of their slopes is -1

comparing what we have with the general form;

y = mx + b

The slope of the given equation is 3/2

To get the slope of other;

3/2 * m = -1

3m = -2

m = -2/3

So we want to write the point-slope equation

y-y1 = m(x-x1)

y-2 = -2/3(x + 1)

3y - 6 = -2x -2

3y = -2x -2 + 6

3y = -2x + 4

y = -2/3x + 4/3

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3 years ago

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$f(x)=\begin{cases}2x&\text{for }x\le1\\bx^2+cx&\text{for }x>1\end{cases}$

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4 years ago

Write the equation of the line perpendicular to y=3/2x+3/2 that passes through the point (-1,2)​

Write the equation of the line perpendicular to y=3/2x+3/2 that passes through the point (-1,2)