Write the equation of the line perpendicular to y=3/2x+3/2 that passes through the point (-1,2)
1 answer:
Answer:
y = -2/3x + 4/3
Step-by-step explanation:
If two lines are perpendicular, the product of their slopes is -1
comparing what we have with the general form;
y = mx + b
The slope of the given equation is 3/2
To get the slope of other;
3/2 * m = -1
3m = -2
m = -2/3
So we want to write the point-slope equation
y-y1 = m(x-x1)
y-2 = -2/3(x + 1)
3y - 6 = -2x -2
3y = -2x -2 + 6
3y = -2x + 4
y = -2/3x + 4/3
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